Question

Pleassse answer quick! (Again..)

Answer 1

Answer:

C) The two functions have the same x-intercept.

Step-by-step explanation:

The given function is

$3x+2y=12$

Let's analyse this function. We can its elements, that is, its slope and y-intercept points by isolating $y$, as follows

$3x+2y=12\\2y=12-3x\\y=\frac{12-3x}{2}\\ y=-\frac{3x}{2}+\frac{12}{2}\\ y=-\frac{3x}{2}+6$

So, the y-intercept is at $y=6$, which is not the same point showed in the graph. The slope of the linear equation is -3/2, which is not the same slope showed in the graph.

From the graph, we can deduct that te y-intercept is at $y=4$, and the slope is 1, because both variables increase at the same rate, which is 4 units, and if you divide 4/4 = 1.

At last, if we calculate the x-intecept of the linear equation, it would be

For $y=0$, let's find $x$

$3x+2y=12\\3x+2(0)=12\\x=\frac{12}{3}\\ x=4$

This means the x-intercept of the linear equation is at 4, and the graph shows the same x-intercept.

Therefore, the two functions have the same x-intercept. So, the right answer is C.

Answer 2

Well for problems like this you need to look at what is plotted. And you need to look at the y intercept which is the vertical line and the x intercept which is the horizontal line. I think the answer is B because of what is plotted. I am not 100% sure but I think it is. Let me try to look into it more but what is this for? Hw assignment?