Valeria is ordering medals for her school's track meet. Company A charges $4.50 for each medal and a one-time engraving fee of $

Question

3 years ago

7

Valeria is ordering medals for her school's track meet. Company A charges $4.50 for each medal and a one-time engraving fee of $

40. Company B charges $6.50 for each medal and a one-time engraving fee of $20. Which inequality can be used to find x, the least number of medals that can be ordered so that the total charge for Company A is less than the total charge for Company B? A) 4.5 + 40x < 6.5 + 20x B) 4.5 + 40x > 6.5 + 20x C) 4.5x + 40 < 6.5x + 20 D) 4.5x + 40 > 6.5x + 20

Mathematics

2 answers:

kiruha [24] · Answer 1 · 2022-04-19T11:41:47+03:00

kiruha [24]3 years ago

6 0

Answer:

The answer is C) 4.5x + 40 < 6.5x + 20

Step-by-step explanation:

Elenna [48] · Answer 2 · 2022-04-19T13:01:08+03:00

Answer:

4.5x + 40 < 6.5x + 20

C is correct

Step-by-step explanation:

Valeria is ordering medals for her school's track meet.

Let total charge be $y and number of medals be x

#Company A charges $4.50 for each medal and a one-time engraving fee of $40.

For company A total charge, y = variable + one time fee

y = 4.5x + 40

#Company B charges $6.50 for each medal and a one-time engraving fee of $20.

For company B total charge, y = variable + one time fee

y = 6.5x + 20

The least number of medals that can be ordered so that the total charge for Company A is less than the total charge for Company B

Company A < Company B

4.5x + 40 < 6.5x + 20

2x > 20

x > 10

Hence, The least value of x is 10 and inequality " 4.5x + 40 < 6.5x + 20 "