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Firlakuza [10]
3 years ago
10

How do u do this?! Please show me how Part A and B especially B!

Mathematics
1 answer:
ella [17]3 years ago
3 0

Check the picture below.

in the picture below, the bottom part

notice, 69° + 21° = 90°, so 21° and 69° are really complementary angles, sharing the same quadrant, meaning for any two sides of lengths say, a,b one angle will have a tangent of say b/a, then the other will have a tangent of a/b.

namely the tangent of each angle, is simply the other's tangent upside-down.

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The figure below shows three squares whose sides form a right triangle. The areas of the two smaller squares are shown in square
mina [271]

Answer:

A:13

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The scale on a map is 2cm =25 miles Dave measured the distance to the next town 5cm How many miles away is the next town
denis-greek [22]

First we need to find the measurement for 1 centimetre. To do this, we need to divide the given amount of miles (25) by the given number of centimetres (2).

25 / 2 = 12.5

1 cm = 12.5 miles

Now we need to find the distance of the next town.

If the next town is 5 cm, and 1 cm is 12.5 miles, we need to multiply 12.5 by 5.

12.5 * 5 = 62.5

<h3>So the next town is 62.5 miles away!</h3>

If you are asked to round this to the nearest whole number, it would be 63 miles.

Hope this helped! <em>Brainliest? :)</em>

7 0
4 years ago
A collection of 30 gems, all of which are identical in appearance, are supposedto be genuine diamonds, but actually contain 8 wo
levacccp [35]

Answer:

Step-by-step explanation:

From the given information:

There are 30 collections of gems, of which 8 are worthless;

Thus, the number of the genuine diamonds = 30 - 8 = 22.

Let X = random variable;

X consider the value as 0 (for  2 worthless stone selection),

X = 1200(1 worthless stone  & 1 genuine stone)

X = 2400 (2 genuine stones selected)

However, the numbers of ways of selecting and chosen Gems can be estimated as:

(^n_r) = (^{30}_2) \\ \\ \implies \dfrac{30!}{2!(30-2)!} \\ \\ \implies \dfrac{30!}{2!(28)!}  \\ \\  \implies \dfrac{30*29*28!}{2!(28)!} \\ \\  \implies  \dfrac{30*29}{2*1} \\ \\ \implies 435

Thus;

Pr (X = 0) = \dfrac{(^8_2)}{435}

Pr (X = 0) = \dfrac{\dfrac{8!}{2!(8-2)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8!}{2!(6)!}}{435}  \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7*6!}{2!(6)!}}{435} \\ \\  Pr (X = 0) = \dfrac{\dfrac{8*7}{2*1}}{435} \\ \\   Pr (X = 0) = 0.0644

P(X =1200) = \dfrac{(^{8}_{1})(^{22}_{1})}{435}

P(X =1200) = \dfrac{ \dfrac{8!}{1!(8-1)!}) ( \dfrac{22!}{1!(22-1)!}) }{435}

P(X =1200) = \dfrac{ (8) ( 22) }{435}

P(X =1200) =0.4046

Pr (X = 2400) = \dfrac{(^{22}_2)}{435}

Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(22-2)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(20)!}}{435}  \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22*21*20!}{2!(20)!}}{435} \\ \\  Pr (X =2400) = \dfrac{\dfrac{22*21}{2*1}}{435} \\ \\   Pr (X = 2400) = 0.5310

To find E(X):

E(X) = (0 × 0.0644) + (1200 × 0.4046)  + (2400 × 0.5310)

E(X) = 0 + 485.52 + 1274.4

E(X) = 1759.92

8 0
3 years ago
Write the product in its simplest form c^7×(-3c)​
sveticcg [70]

Answer:

-3c^8

Step-by-step explanation:

3 0
3 years ago
Let P(x) be the statement"x= x2", If the domain consists of the integers, what are these truth values? (a) P(0) (b) P(1) (c) P(2
jeka57 [31]

Answer: i guess the problem is with P(x) => "x = x^{2}", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and 0^{2} = 0. So p(0) is true.

b) x = 1 and 1^{2} = 1, so P(1) is true.

c) x = 2, and 2^{2} = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and 1^{2} = 1, and 1 ≠ -1, so P(-1) is false.

6 0
3 years ago
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