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3 years ago

|3−10|−(12÷4+2)^2

Mathematics

2 answers:

g100num [7]3 years ago

7 0

Ok so follow PEMDAS 
|3−10|−(12÷4+2)^2
|-7|-(3+2)^2
7-(5)^2
7-25
-18

sweet-ann [11.9K]3 years ago

4 0

Using PEMDAS you'd start with the parentheses
(12/4+2)
(3+2)
(5)^2
then square it, but dont forget about the negative
5^2=25
|3-10|-25
then 3-10 is -7 but the absolute value makes it positive
so
7-25 would turn out to be -18

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CLASS 6 MATHS!!!! HELP ME PLEASE!!!!!!!

Elanso [62]

Step-by-step explanation:

$\\ 20. \: \: ( \frac{ - 3}{4} )(4\frac{1}{6} )$

$\\ = \frac{ - 3}{4} \times \frac{25}{6}$

$\\ = \frac{ - 25}{8}$

$\\ = - 3.125$

$\\ 21. \: \: ( - 3\frac{7}{8} )( - 5\frac{3}{4} )$

$\\ = \frac{ - 31}{8} \times \frac{ - 23}{4}$

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6 0

3 years ago

The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time

pickupchik [31]

Answer:

$N_c \approx 5.0$

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production $T_w=0.25day$

Average processing time is $T_a=0.15 day per container$

Wheel per container $N_w=200$

Total wheel per day $D=2000$

Policy variable of $X=5%$

Generally the equation for Total number of container $N_c$ is mathematically given by

$N_c=DT(\frac{1+X}{N_w} )$

Where

Total time $T=T_w+T_a$

$T=0.15+0.25$

Therefore

$N_c=DT(\frac{1+X}{N_w} )$

$N_c=2000*0.40(\frac{1+0.5}{200} )$

$N_c=(\frac{840}{200} )$

$N_c=4.2$

$N_c \approx 5.0$

Therefore the number of Kanban containers needed for the wheels is

$N_c \approx 5.0$

3 0

3 years ago

2) Evaluate the given numerical expression. A) 9 B) 12 C) 14 D) 21

eduard

Answer:

$\boxed{\sf{14}}$

Step-by-step explanation:

$\boxed{\underline{\text{ORDER OF OPERATIONS:}}}$

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

PEMDAS

Parentheses
Exponents
Multiply
Divide
Add
Subtract

BODMAS

Brackets
Order
Divide
Add
Subtract

First, do parentheses.

3+6*(5+4)÷3-7

(5+4)=9

$\Longrightarrow: \sf{3+6* 9\div 3-7}$

Do multiply and divide.

6*9=54

54/3=18

Then, rewrite the problem down.

$\Longrightarrow: \sf{3+18-7}$

Add.

$\sf{3+18=21}$

$\sf{21-7=\boxed{\sf{14}}$

$\Longrightarrow: \boxed{\sf{14}}$

Therefore, the correct answer is "C. 14".

I hope this helps, let me know if you have any questions.

8 0

3 years ago

A cylindrical pressure vessel has a height of 9 feet and a diameter of 6 feet. how much gas can the pressure vessel hold when fu

bezimeni [28]

Step-by-step explanation:

the volume of a cylinder is as for any other regular 3D object :

ground area ×height

the ground area of a cylinder is a circle, so it is

pi×radius² × height

the radius is always half of the diameter (of the diameter is airways twice the radius).

radius = 6/2 = 3 ft.

the volume is then

pi × 3² × 9 = pi × 9 × 9 = pi × 81 ft³

so, the answer is 81pi ft³.

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2 years ago

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densk [106]

Answer:

0.2.34

That is probs the answer for B

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3 years ago