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3 years ago

|3−10|−(12÷4+2)^2

Mathematics

2 answers:

g100num [7]3 years ago

7 0

Ok so follow PEMDAS 
|3−10|−(12÷4+2)^2
|-7|-(3+2)^2
7-(5)^2
7-25
-18

sweet-ann [11.9K]3 years ago

4 0

Using PEMDAS you'd start with the parentheses
(12/4+2)
(3+2)
(5)^2
then square it, but dont forget about the negative
5^2=25
|3-10|-25
then 3-10 is -7 but the absolute value makes it positive
so
7-25 would turn out to be -18

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10x+7=12x-5 what is x

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3 years ago

the cost of 5 cans of dog food is $4.35. at this price how much do 11 cans of dog food cost explain your reasoning. ASAP

mestny [16]

Answer:

Cost of 11 cans of Dog food is $9.57

Step-by-step explanation:

Cost of 5 cans of dog food = $4.35

So to find out the cost of 11 cans of dog food at the same price, we need to calculate the price of 1 can of dog food.

Calculation for finding out cost of 1 can of dog food

The price $4.35 which is given is the price of 5 cans

So to find the cost of 1 can, we need to divide the given price by 5

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3 years ago

Find the values of x work 10% of my grade

Ostrovityanka [42]

Answer:

x = 35

Step-by-step explanation:

1. Add all angles

$115+(x+36)+24+(2x+10)+2x$

= $5x+185$

2. Match 360 and fix

$5x+185=360$

$5x=360-185$

$5x=175$

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2 years ago

Read 2 more answers

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago

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Rudiy27

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So the first showing had begun at 2:30 and had ended at 4:55. By substracting 2:30 from 4:55 we get 2:25 - that's the duration of the video.

The answer is 2 hours and 25 minutes.

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3 years ago

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