Answer:
Step-by-step explanation:
<u>Prime factors of 2100 are:</u>
<u>The single-digit divisors are:</u>
- 1, 2, 3, 2*2= 4, 5, 2*3= 6, 7
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<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>
- 2100/1 = 2100, yes
- 2100/2 = 1050, yes
- 2100/3 = 700, yes
- 2100/4 = 525, yes
- 2100/5 = 420, yes
- 2100/6 = 350, yes
- 2100/7 = 300, yes
- 2100/8 = 262.5, no
- 2100/9 = 233.33, no
So all the numbers from 1 to 7
Answer:
The solution is given below:
Step-by-step explanation:
As we know the value of k and r so the equation will be
Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Answer:
Step-by-step explanation:
Expected payment= 0.000514*55000= 28.27
which would round to 29
1/5 is equal to 2/10 so the one with 3/10 has more
