Answer:
quadrant 4
Step-by-step explanation:
<u>Answer:</u>


<u>Step-by-step explanation:</u>

First set the equation to 0


Second, get the 12 on the right side of the equal sign by adding a -12 to each side



Square root both sides of the equal sign.


Take the square root on left sides of the equal sign.


Take the square root on the right side of the equal sign. Remember 



<u>AND</u>

Answer:
Step-by-step explanation:
k
Answer:

Step-by-step explanation:

So, 
= 
Hope this helps :)