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scZoUnD [109]
3 years ago
11

Hi ! if you come across this can you please help me out?:) tysm

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0

Answer: y=4x-2

Step-by-step explanation:

Since you are looking for y-intercept, the point has to be on the vertical line and the slope is 4 so it has to go up 4 to the right 1

You might be interested in
Write 350 as a product of primes. Use index notation when giving your answer
Mkey [24]

Answer:

5² x 7 x 2

Step-by-step explanation:

350

= 35 x 10

= 7 x 5 x 5 x 2

= 5² x 7 x 2

8 0
2 years ago
tickets at a particular movie theatre have different rates for adults and children. on a friday the theatre sold 4 adult tickets
maria [59]
Using elimination method. Using substitution will cause some fraction problems.

c- child tickets
a- adult tickets

4a + 7c = $83
5a + 6c = $90

multiply by -5

-20a - 35c = -$415
20a + 24c = $360

-11c= -$55
c = $5 child tickets

4a + 7(5)= $83

4a + 35 = $83

4a = $48

a= $12 adult tickets

4 0
3 years ago
Multiply the following complex numbers:<br>(7-3i)(8 + 4i)​
mel-nik [20]

Answer:

A

Step-by-step explanation:

Noting that i² = - 1

Given

(7 - 3i)(8 + 4i) ← expand factors using FOIL

= 56 + 28i - 24i - 12i²

= 56 + 4i - 12(- 1)

= 56 + 4i + 12

= 68 + 4i → A

3 0
3 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
Mrs. Jones purchased 6.2 pounds of ground beef. She cooked 0.5 of the ground beef. How many pounds of ground beef did she cook?​
Anvisha [2.4K]

Answer:

She cooked 3.1 pounds

Step-by-step explanation:

6.2 x 0.5 = 3.1

5 0
3 years ago
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