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2 years ago

The x value l’s in quadrant II are always

Mathematics

1 answer:

AnnZ [28]2 years ago

8 0

Answer:

The value of x in the 2nd quadrant is always negative.

Step-by-step explanation:

There form four zones in the coordinate plane by placing the coordinate axes i.e. X-axis and Y-axis. The top right zone is called the 1st quadrant and 2nd, 3rd and 4th quadrants are the zones obtained by rotating in anticlockwise about the origin.

Since the 2nd quadrant is placed at the top left zone, so, we have to move in the negative x-direction along or parallel to the X-axis and to move in the positive y-direction along or parallel to the Y-axis.

Therefore, the value of x in the 2nd quadrant is always negative.

(Answer)

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segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0

3 years ago

My last problem and I'm stuck please help!!

WITCHER [35]

Answer is C= -125,125

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3 years ago

Help !!What is the value of q

Advocard [28]

it should be 16.5 because the other chord, half of it is 8.25. good luck!

5 0

3 years ago

A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground.

tankabanditka [31]

To find the length of the ladder, you need to do Pythagorean theorem.
50^2 + 30^2 = x^2
2500 + 900 = x^2
x^2 =3400
x= square root of 3400
58.31 OR 10 root34

To find the angle:
tan theta = opposite/adjacent
50/30 = 5/3
theta = tan inverse of 5/3
= 59.04

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3 years ago

Is -97.6590 less than -90 29/44

weqwewe [10]

Yes -97.6590 is less than -90 29/44

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3 years ago

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