Answer:
For the code we have 3 selections.
The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}
So we have 5 options.
The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)
So here we have 27 - 5 = 22 options
The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.
Here we have 22 - 1 = 21 options.
The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:
C = 5*22*21 = 2310.
There are 2310 different possible codes
36 x 24=864 whole poster
5 x 12=60 cut part
864 - 60= 804 part that remains
;)
step-by-step explanation:
every time we see "a number" or "the same number," we can add a variable (we'll use x here). rewriting the problem, we get: 8 less than 2 times x is gr8er than the sum of x and 9.
next, we can work backwards to write an inequality. we know from the word problem above that the number on the left side of the equation is 8 less than 2x, so we can rewrite that part like this: 2x-8.
for the right side of the equation, all we have to do is simplify "the sum of x and 9" to x + 9. so now the inequality should look like this: 2x - 8 > x + 9.
now we'll solve the inequality just like an equation: subtract x from both sides of the inequality, so now we have: x - 8 > 9.
then, we can add 8 to both sides to get the x by itself, and we get the answer: x > 15
hope this helps! <em>:)</em>
<span>c. Peter walks at a rate of 13/4 miles per hour.</span>
The slope is 1/6. y= mx + b
m is always to slope.
