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liraira [26]
3 years ago
7

PLZZZZZZZZZZZZZZZZ HELP IM IN A RUSH

Mathematics
2 answers:
Ratling [72]3 years ago
8 0

B

the average temperature rose by + 5°

this years average = - 19 + 5 = - 14°


olga55 [171]3 years ago
7 0
B .....................
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Put the steps in correct order to prove that if x is irrational, then 1/x is irrational using contraposition.
SOVA2 [1]

Answer:

The correct order is:

a

c

d

b

Step-by-step explanation:

First, let's write 1/x in a convenient way for us:

a) Substitute 1/x = p/q, to obtain x = 1/(1/x) = 1/(p/q) = q/p.

Now we assume that 1/x is rational (we want to prove that this implies that x will be also rational and because we know that x is irrational assuming that 1/x is rational will lead to an incongruence), then:

c. If 1/x is rational, then 1/x = p/q for some integers p and q with q ≠ 0. Observe that p is not 0 either, because 1/x is not 0.

Now we know that we can write x as a quotient of two integers, we need to imply that, then the next one is:

d) Observe that x is the quotient of two integers with the denominator nonzero.

And that is the definition of rational, then we end with:

b) Hence x is rational.

Which is what we wanted to get.

5 0
2 years ago
Rich is comparing the cost of maintaing his car with the depreciating value of the car. When will the cost and value be the same
goldfiish [28.3K]

Complete question:

Rich is comparing the cost of maintaining his car with the depreciation value of the car.

The value starts at $20,000 and decreases by 15% each year. The maintanance cost is $500 the first year and increases by 28% per year.

When will the maintenance cost and the value be the same.

Answer:

9 years

Step-by-step explanation:

Depreciation is modeled by an exponential function :

A = p(1 - r)^t [decrease, '-']

A = 20,000(1 - 0.15)^t

A = 20000(0.85)^t - - - (1)

Maintainace cost :

A = p(1 + r)^t ; [increase, '+']

A = 500(1 + 0.28)^t

A = 500(1.28)^t - - - (2)

Equating (1) and 2

20000(0.85)^t = 500(1.28)^t

1.28^t / 0.85^t = 20000/500

(1.28 / 0.85)^t = 40

Take log of both sides

Log (1.28 / 0.85)^t = log 40

t * 0.1777910 = 1.6020599

t = 1.6020599 / 0.1777910

t = 9.01

t = 9 years

8 0
3 years ago
Ordered pair for this point? (I circled the point in Pink)
Andreyy89

Answer:

(-4,-3)

Step-by-step explanation:

The first coordinate of the ordered pair is the x value or go across

to the right is positive  and the left is negative   so x = -4

The second coordinate of the ordered pair is the y value or go up and down

up is positive and down is negative  so y = -3

(-4,-3)

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME I ASAP<br><br>I WILL MARK YOU BRAINLIEST
kramer
<h3>Function 1 : </h3>

Observe the abscicca and ordinates

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>y-coordinate</em><em> </em><em>is</em><em> </em><em>ordinate</em><em> </em><em>and</em><em> </em><em>x-coordinate</em><em> </em><em>is</em><em> </em><em>abscicca</em><em>.</em>

  • The ordinate having 0 as abscicca in function 1 is (0,1), Thus.. The y-intercept is 1

<h3>Function 2 : </h3>

Observe the graph and mark the point where function meets y-axis

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>point</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>graph</em><em> </em><em>where</em><em> </em><em>the</em><em> </em><em>function</em><em> </em><em>meets</em><em> </em><em>y-axis</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>y-intercept</em><em>.</em>

  • The point where the function meets is (0,1). Therefore, The y-intercept of function 2 is also 1

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<em><u>Thus, Option C is the correct choice!!~</u></em>

7 0
2 years ago
There are currently 21 frogs in a (large) pond. The frog population grows exponentially, tripling every 7 days. How long will it
Xelga [282]
Let x =  number of days

The initial number of frogs  = 21.
The number of frogs triples every 7 days.
The exponential function that models the number of frogs with respect to the number of days is
y = 21(3^{x/7} )

When the population is 150, then
21(3^{x/7}) = 150 \\\\ 3^{x/7} = 150/21 \\\\  \frac{x}{7} ln(3) = ln(150/7) \\\\ x = 7(  \frac{ln(150/21)}{ln(3)} ) = 12.527&#10;
A graph of y versus confirms the answer.

Answer:  12.5 days

7 0
3 years ago
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