Answer:
16 people
Step-by-step explanation:
This is a set problem
let first session be a
let second session be b
128 people attended at least one session = a∪b
a. 3/4 attended both session 1&2 = a∩b
b. 7/8 attended session 2 = p(b) i.e population b
c x attended session 1 = p(a) i.e. population a
lets get the figures.
- For both sessions 3/4 × 128 = 96 = a∩b
- For second session 7/8 × 128 = 112 = b
- The formular is a∪b = p(a) + p(b) - a∩b
- a∪b = 128 (they at least one session)
lets substitute into the equation
let p(a) be x
128 = x + 112 - 96
128 = x + 16
x = 112 - no of people that attended the morning session.
But to find those that ONLY attended morning session
x - a∩b
112 - 96 = 16
Answer:
3:45 PM.
Step-by-step explanation:
We have been given that on Thursday afternoon at camp Alice played basketball and went swimming before dinner she spent 45 minutes playing basketball and one hour swimming dinner lasted for an hour. The dinner ended at 5:30 PM.
Since she spent 1 hour for swimming, so 1 hour before 5:30 PM would be 4:30 PM.
To find the time, when Alice started playing basketball, we need to find 45 minutes before 4:30 PM.
30 minutes before 4:30 PM would be 4:00 PM and 15 minutes before 4:00 PM would be 3:45 PM.
Therefore, Alice started playing basket ball at 3:45 PM.
Answer:
There's no negative sign in front of the absolute value so it opens upward. As for the vertex, the x value will be whatever makes what is in the absolute value symbols 0 which is 2.5 in our case and the y-coordinate is 3 so the vertex is (2.5, 3).
Thank you so much for the tip
