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Tomtit [17]
3 years ago
8

Nine qualified applicants apply for a part-time job. If the manager randomly hires 3 of them, what is the probability that he hi

res the 3 oldest?
Mathematics
2 answers:
anastassius [24]3 years ago
5 0
1/3*1/4*1/7= 1/84
It is 9c3
AnnyKZ [126]3 years ago
5 0
There are 3!  = 6 ways he can pick the 3 oldest people
Total number of permutations  of any 3 from 9 = 9P3 =  9*8*7 = 504

so required probability = 6 / 504 = 1/84
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Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.
aev [14]

81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

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∵ The binomial is 81 a² - 25 z^{6}

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∵ \sqrt{25} = 5

∵ \sqrt{z^{6}} = z³

∴ \sqrt{25z^{6}}=5z^{3}

- The two terms have square root

∵ The sign between them is (-)

∴ 81 a² - 25 z^{6}  is a difference of two squares

∵ Its factorization is two identical brackets with different

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∵ 81 a² = 9a × 9a

∵ 25 z^{6} = 5z³ × 5z³

- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 z^{6} = (9a + 5z³)(9a - 5z³)

81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

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8 0
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