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Tomtit [17]
4 years ago
8

Nine qualified applicants apply for a part-time job. If the manager randomly hires 3 of them, what is the probability that he hi

res the 3 oldest?
Mathematics
2 answers:
anastassius [24]4 years ago
5 0
1/3*1/4*1/7= 1/84
It is 9c3
AnnyKZ [126]4 years ago
5 0
There are 3!  = 6 ways he can pick the 3 oldest people
Total number of permutations  of any 3 from 9 = 9P3 =  9*8*7 = 504

so required probability = 6 / 504 = 1/84
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A math club has a total of 41 girls and boys in it. The number of girls is 5 more than 2 times the number of boys.
Vinvika [58]

Answer:

the answer is an orgy

Step-by-step explanation:

there is no way that many girls and boys are in the same room without having an orgy...

3 0
3 years ago
What is the measure of angle x? need help asap <br>​
Blizzard [7]

Answer:

83! :)

Step-by-step explanation:

It all equals 180.

So,

53+44+?=180

180-53-44=83! :)

83+53+44=180! :)

7 0
3 years ago
Read 2 more answers
60 minutes it 20% of blank minutes
nikdorinn [45]
We have a proportion: 60/?= 20/100

Cross multiply:
20*?= 60*100
⇒ ?= 60*100/20= 300

60 minutes is 20% of 300 minutes~
5 0
4 years ago
#2 <br> #3 <br> Need help for my discrete math class
miss Akunina [59]

For (2), start with the base case. When n = 2, we have

(n + 1)! = (2 + 1)! = 3! = 6

2ⁿ = 2² = 4

6 > 4, so the case of n = 2 is true.

Now assume the inequality holds for n = k, so that

(k + 1)! > 2ᵏ

Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have

((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!

Then by our hypothesis,

(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹

and k•2ᵏ ≥ 2•2² = 8, so

k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹

which proves the claim.

Unfortunately, I can't help you with (3). Sorry!

3 0
3 years ago
A normal population has a mean of 12.2 and a standard deviation of 2.5. compute the z value associated with 14.3. what proportio
Citrus2011 [14]
The z-score associated with 14.3 is 0.84.  0.2995 of the population is between 12.2 and 14.3.  0.1894 of the population is less than 10.0.

The formula for a z-score is

z=(X-μ)/σ

With our data, we have:
z=(14.3-12.2)/2.5=0.84

The z-score associated with the mean is 0.5.  To find the proportion of the population between the mean and 14.3, subtract 0.7995 (the proportion of population below the z-score of 0.84, using http://www.z-table.com) and 0.5:

0.7995 - 0.5 = 0.2995.

The z-score for 10.0 is

(10.0-12.2)/2.5 = -0.88.  The proportion of the population less than this is 0.1894.
5 0
3 years ago
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