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AlladinOne [14]
3 years ago
6

Two figures have all of their corresponding angles congruent. Can you conclude that the figures are similar? Explain your answer

.
Mathematics
1 answer:
rodikova [14]3 years ago
8 0
Yes, we can conclude that two figures are similar because similar figures can have congruent angles without the need of congruent sides, so as long as its the same shape but not exactly the same side it can be proven that the figures are similar.
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In a test of a printed circuit board using a random test pattern, an array of 16 bits is equally likely to be 0 or 1. Assume the
Doss [256]

Answer:

A) b) and c) answer has been explained below.

Step-by-step explanation:

For the question would use 1's and 0's and taking probabilities to be equal for both using random test pattern whose formula is when p = q

then Simplify to

P[k] =  nCk /2^n

A.Probability that all bits are 1s

16c16/2^16 = 1/65536

B. Probability that all bits are 0s

16c0/2^16 = 1/65536

C.the probability that exactly 8 bits are 1s and 8 bits are 0s

16c8/2^16 = 12870/65536 =>0.1963 ≈ 19.63%

8 0
4 years ago
any help will be helpful and you have to make ur own graph paper if you don't have none he said but please help I don't understa
ivann1987 [24]

Step-by-step explanation:

do you need graph paper?

just minus the 2nd cordnates x to the 1dt cordnates x and same for the y. that will give you the distance for each x and y points

8 0
3 years ago
Help will mark brainliest............
Nataliya [291]
The answer is 90, Because angle D is a 90 degree angle, and 180- 90=90, so the answer is 90.
7 0
3 years ago
Find the x- and y intercepts for the linear equation
Vanyuwa [196]

4. 3x + 2y = 6

x-intercept = 2 ,  y - intercept = 3

5. 4x – 9y = 36

x-intercept = 9, y - intercept = -4

6. x + y = -3

x-intercept = -3, y - intercept = -3

8. x - 3y = 12

x-intercept = 12, y - intercept = -4

Step-by-step explanation:

To find the x-intercept we put y=0 in the equation and to find the y-intercept we put x = 0 in the equation

<u>4. 3x + 2y = 6</u>

Putting y = 0

3x + 2y = 6\\3x +2(0) = 6\\3x = 6\\\frac{3x}{3} = \frac{6}{3}\\x= 2

Putting x=0

3x + 2y = 6\\3(0) + 2y = 6\\2y = 6\\\frac{2y}{2} = \frac{6}{2}\\y= 3

<u>5. 4x – 9y = 36</u>

Putting y = 0

4x -9y = 36\\4x - 9(0) = 36\\4x = 36\\\frac{4x}{4} = \frac{36}{4}\\x = 9

Putting x=0

4(0) -9y = 36\\-9y=36\\\frac{-9x}{-9} = \frac{36}{-9}\\x =-4

<u>6. x + y = -3</u>

Putting y = 0

x+y=-3\\x+0 = -3\\x = -3

Putting x=0

x + y = -3\\0+y=-3\\y=-3

<u>8. X - 3y = 12</u>

Putting y=0

x - 3(0) = 12\\x -0 = 12\\x = 12

Putting x = 0

0-3y = 12\\-3y = 12\\\frac{-3y}{-3} =\frac{12}{-3}\\y=-4

Keywords: Linear equation

Learn more about linear equations at:

  • brainly.com/question/2150928
  • brainly.com/question/2154850

#LearnwithBrainly

3 0
3 years ago
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\&#10;P(x)=3x^3-5x^2-14x-4\\\\&#10;D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\&#10;\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\&#10;3x^3-5x^2-14x-4=0\\\\&#10;

\displaystyle\\&#10;\text{Verification}\\\\&#10;3x^3-5x^2-14x-4=\\\\&#10;=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\&#10;=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\&#10;=-\frac{6}{9}+\frac{14}{3}-4=\\\\&#10;=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\&#10; =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\&#10;\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\&#10;\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\&#10;3x^3-5x^2-14x-4=0\\&#10;~~~~~-5x^2 = x^2 - 6x^2\\&#10;~~~~~-14x =-2x-12x \\&#10;3x^3+x^2 - 6x^2-2x-12x-4=0\\&#10;x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\&#10;(3x+1)(x^2-2x -4)=0\\\\&#10;\text{Solve: } x^2-2x -4=0\\\\&#10;x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\&#10;x_1 =1+\sqrt{5}\\&#10;x_2 =1-\sqrt{5}\\&#10;\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
3 years ago
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