Answer:
Dilation by a scale factor of 2 followed by a reflection over the y axis.
Step-by-step explanation:
The Y-axis is the vertical axis. So that cancels out the two about the x-axis. Then I counted the length of both triangles bases. Luckily for this one their bases aren't tilted but just flat. The big one is 6 and the small 3. Since it is going from one to the other you must find what number completes their equation. 3x = 6.
2
So that's how I got the last part of the problem
Sorry if this doesn't make sense. It seems just like ramble but it should help.
Answer:
Step-by-step explanation:
Left
When a square = a linear, always expand the squared expression.
x^2 - 2x + 1 = 3x - 5 Subtract 3x from both sides
x^2 - 2x - 3x + 1 = -5
x^2 - 5x +1 = - 5 Add 5 to both sides
x^2 - 5x + 1 + 5 = -5 + 5
x^2 - 5x + 6 = 0
This factors
(x - 2)(x - 3)
So one solution is x = 2 and the other is x = 3
Second from the Left
i = sqrt(-1)
i^2 = - 1
i^4 = (i^2)(i^2)
i^4 = - 1 * -1
i^4 = 1
16(i^4) - 8(i^2) + 4
16(1) - 8(-1) + 4
16 + 8 + 4
28
Second from the Right
This one is rather long. I'll get you the equations, you can solve for a and b. Maybe not as long as I think.
12 = 8a + b
<u>17 = 12a + b Subtract</u>
-5 = - 4a
a = - 5/-4 = 1.25
12 = 8*1.25 + b
12 = 10 + b
b = 12 - 10
b = 2
Now they want a + b
a + b = 1.25 + 2 = 3.25
Right
One of the ways to do this is to take out the common factor. You could also expand the square and remove the brackets of (2x - 2). Both will give you the same answer. I think expansion might be easier for you to understand, but the common factor method is shorter.
(2x - 2)^2 = 4x^2 - 8x + 4
4x^2 - 8x + 4 - 2x + 2
4x^2 - 10x + 6 The problem is factoring since neither of the first two equations work.
(2x - 2)(2x - 3) This is correct.
So the answer is D
Answer:
'<em>We </em><u>cross</u><em> </em><u>multiplied</u><em> it'</em>.
Step-by-step explanation:
Lets first understand our proportion and re write in correct Fraction form as:
Eqn(1).
where:
and
are the Numerators
and
are the Denominators
Now the question sais that Eqn(1). can be written as
![ad=bc](https://tex.z-dn.net/?f=ad%3Dbc)
This is true since here:
'<em>We </em><u>cross</u><em> </em><u>multiplied</u><em> it'</em>.
<em>Cross Multiplication is used when we have equations of the form Eqn(1) where there is one fraction on the left hand side and one fraction on the right hand side, so that the Numerator of the left hand side is multiplied with the Denominator of the right hand side and similarly the Denominator of the left hand side is multiplied with the Numerator of the right hand side (like a diagonal multiplication). </em>
1 yard = 3 feet = 36 in
so 1 in = 1/36 yard, 1 ft = 1/3 yard.
The volume of the layer of the topsoil, is:
5 in * 23 ft * 17 ft = 5 *(1/36)*23*(1/3)*17*(1/3) yard cubed =
(5*23*17)/(36*3*3)= 1955/324=6.034 yard cubed.
The store only sells increments of 1/4 = 0.25 cubic yards.
we need 6.034/0.25=24.136
So we need to buy 25 (24 will not be enough) increments of 1/4 cubic yards.
Answer: 25 increments of 1/4 cubic yard, that is 25*0.25=6.25 cubic yards.