the answer is 43580627.44 according to my calculations!
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:


h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
Answer:
t= 24.75 days
Step-by-step explanation:
Here A(t) is the amount of the element that remains after some time. So they tell us that find the time it takes to basically have 4 grams remaining so A(t) = 4
4 = 10 * 0.5 ^ (t/18.72)
0.4= 0.5 ^ (t/18.72)
t= 24.75 days
Answer should make sense because half life is around 18 days which means to go from 10 g to 5g would be somewhere around 18 days but we are going to 4 g so it takes more days
Answer:
Im not exactly sure but i think it's 1/4 or 1/5.
Step-by-step explanation:
This was based on my work I did.
Answer:
Cos x = 1 -
+
-
+ ...
Step-by-step explanation:
We use Taylor series expansion to answer this question.
We have to find the expansion of cos x at x = 0
f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x
Now we evaluate them at x = 0.
f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1
Now, by Taylor series expansion we have
f(x) = f(a) + f'(a)(x-a) +
+
+
+ ...
Putting a = 0 and all the values from above in the expansion, we get,
Cos x = 1 -
+
-
+ ...