Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
1,000 because kilometers is 1,000 is how many is for 2 but for one it's 500
N = {15 +- root of ( 225 + 64) } / 2
= {15 +- root of 289 } / 24
= 15 + 17 } / 2 or { 15 -17 } /2
= 16 or -1
(4)^2 must be done first.
That’ll give you 16. (4x4)
16 x -2= -32
-32+4= -28
