Answer:
(2x-1)(x-7)
Step-by-step explanation:
Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.
![\begin{tabular} {|c|c|c|c|c|c|} &Frequently&Occassionally&Not at all&Total\\[1ex] Male&227&454&798&1,479\\ Female &205&450&747&1,402\\ Total&432&904&1,545&2,881 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0A%20%26Frequently%26Occassionally%26Not%20at%20all%26Total%5C%5C%5B1ex%5D%0AMale%26227%26454%26798%261%2C479%5C%5C%0AFemale%20%26205%26450%26747%261%2C402%5C%5C%0ATotal%26432%26904%261%2C545%262%2C881%0A%5Cend%7Btabular%7D)
Part A:
If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

Part B:
If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

Part C:
If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

Part D:
If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

Part E:
The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.
Indeed from the table, there are 205 females who are frequently involved in charity work.
Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
<em>Answer:840 hours</em>
<em>Step-by-step explanation:You have to Add to get your answer.This is how I got 840:</em>
60+60=120
120+720=840
Your answer is:840 hours
hope this was helpful :)
I feel like it would be mean or median, because there is no outlier, making it so that all of the numbers are closely put together.
Put the set into order.
25, 26, 27, 28, 29
So, we know that this is all in order, making it so that we know for sure that there is no outlier.
If you find the mean, it'll represent the data nicely.
We know that both the mean and median represent the data set nicely, because it just does. It's one of those things that are extremely painful and hard to fully explain and have someone understand, but don't worry, it makes sense.
So, it can't just be the mean only or the median only.
It also can't be the mode only, because THERE IS NO MODE!
So, our final answer is mean or median :)
~Hope I helped!~
Step-by-step explanation:
1) A number <em>m</em> is at least four
<em>m ≥ 4 ['at least' = ≥ symbol]</em>
<em />
2) 4x ≤ 20x; x=2
4(2) ≤ 20(2)
8 ≤ 40
[Im not sure if this is a solution or and inequality :/ ]
3) x < 5
--> On the line, draw the number 0, and the number five. 'x < 5' also means 'x is less that five.' So, draw a dot over the line before 5, and make an arrow going to the left of the page,
<-----------------------------------o 5
<---|---|---|---|---|---|---|---|---|---|---|---|---|---|--->
0
Hopefully this helps! :)