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Alex Ar [27]
3 years ago
9

Find the lateral area for the given prism. 1,092 cm^2 998 cm^2 1,272 cm^2 870 cm^2

Mathematics
1 answer:
storchak [24]3 years ago
3 0
This might help some this is mine from a little bit age =^-^=
Download pdf
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Factor completely.<br>2x^2 – 15x + 7​
KonstantinChe [14]

Answer:

(2x-1)(x-7)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the probability that the person is frequently or occasionally involved in charity work.
Schach [20]
Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.

\begin{tabular}&#10;{|c|c|c|c|c|c|}&#10; &Frequently&Occassionally&Not at all&Total\\[1ex]&#10;Male&227&454&798&1,479\\&#10;Female &205&450&747&1,402\\&#10;Total&432&904&1,545&2,881&#10;\end{tabular}

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}



Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

P(being&#10; \ female \ or \ not \ being \ involved)\\ \\= &#10;\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = &#10;\frac{2200}{2881}=\bold{0.764}



Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

P(being&#10; \ male \ or \ being \ frequently \ involved)\\ \\= &#10;\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = &#10;\frac{1684}{2881}=\bold{0.585}



Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

P(being&#10; \ female \ or \ not \ being \ frequently \ involved)\\ \\= &#10;\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = &#10;\frac{2654}{2881}=\bold{0.921}



Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".
4 0
3 years ago
A car drives 60 miles per hour. Write and solve an equation to find the number of hours it takes the
olga_2 [115]

<em>Answer:840 hours</em>

<em>Step-by-step explanation:You have to Add to get your answer.This is how I got 840:</em>

60+60=120

120+720=840

Your answer is:840 hours

hope this was helpful :)

4 0
3 years ago
What measure of center best represents the data set?
inysia [295]
I feel like it would be mean or median, because there is no outlier, making it so that all of the numbers are closely put together.

Put the set into order.

25, 26, 27, 28, 29

So, we know that this is all in order, making it so that we know for sure that there is no outlier. 

If you find the mean, it'll represent the data nicely. 

We know that both the mean and median represent the data set nicely, because it just does. It's one of those things that are extremely painful and hard to fully explain and have someone understand, but don't worry, it makes sense.

So, it can't just be the mean only or the median only.

It also can't be the mode only, because THERE IS NO MODE! 

So, our final answer is mean or median :)

~Hope I helped!~
7 0
4 years ago
Only t circled ones somebody plz help I am gonna get a 0 plz help I will give you brainleist
Vikki [24]

Step-by-step explanation:

1) A number <em>m</em> is at least four

<em>m ≥ 4  ['at least' = ≥ symbol]</em>

<em />

2) 4x  ≤ 20x; x=2

4(2) ≤ 20(2)

8 ≤ 40

[Im not sure if this is a solution or and inequality :/ ]

3)  x < 5

--> On the line, draw the number 0, and the number five. 'x < 5' also means 'x is less that five.' So, draw a dot over the line before 5, and make an arrow going to the left of the page,

<-----------------------------------o   5

<---|---|---|---|---|---|---|---|---|---|---|---|---|---|--->

                          0

Hopefully this helps! :)

4 0
3 years ago
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