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iogann1982 [59]
3 years ago
8

Another easy question for brainilist...................

Mathematics
2 answers:
Kryger [21]3 years ago
7 0

Answer:

  The <em>first choice</em> is the correct one.

Step-by-step explanation:

I find it easier to deal with inequalities of this sort if I arrange the inequality symbol so it points to the left (<). This puts the expressions in the same order as they appear on the number line (left is less than right).

Doing that, your choices are ...

  • -3 < 4 . . . . TRUE
  • 4 < -3 . . . . false
  • -2 < -3 . . . false
  • -3 < -6 . . . false

FromTheMoon [43]3 years ago
4 0

Answer:

the first one

Step-by-step explanation:

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\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad &#10;radius=\stackrel{\sqrt{40}}{ r}&#10;\\\\\\\&#10;[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
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melamori03 [73]

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

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