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Artist 52 [7]
3 years ago
8

Three equivalent ratios for 22:55

Mathematics
2 answers:
Rasek [7]3 years ago
6 0
2:5
4:10
66:165 

Is that correct? 
Dafna11 [192]3 years ago
3 0
2.255, 225.5 and 0.2255 I know this because you have to move the decimal point and it equals the same thing hope it helps
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Can someone please help me with #3?
kap26 [50]

Answer:


Step-by-step explanation:

First, make sure you know which section of the number line you want as 1 and 2. Next, put 0.25 not right at 0 but very close, then put 0.75 farther but not too much from 0.25. Then for the decimal 1.99 put that very close to where you marked the 2 but, not on the 2. Finally, put 2.03  very close to 2 but not exactly on the 2. Also, make sure that the number line is marked evenly.

7 0
3 years ago
Graph -7x+5y=35. khan acadmy forms of linear equations question. pls show work (10 points)
a_sh-v [17]

Answer:

Below

Step-by-step explanation:

● -7x + 5y = 35

Add 7x to both sides

● -7x +7x + 5y = 35+7x

● 5y = 7x + 35

Divide both sides by 5

● 5y/5 = (7x+35)/5

● y = 1.4x + 7

The graph of the function:

8 0
3 years ago
Read 2 more answers
The length of a rectangle is twice the width. If the perimeter of the rectangle is 60 units, find the area of the garden.​
AlexFokin [52]
Perimeter = (length+width) x 2


Let w units be the width of the rectangle.

Length of the rectangle = 2w

Perimeter:
(2w+w) x 2 = 60

(3w)2 = 60

6w = 60

w = 10


Area:
2(10) x 10

= 20 x 10

= 200 units

4 0
2 years ago
3. Find two possible lengths for CD if C, D, and E
Kaylis [27]

Given :

C, D, and E  are col-linear, CE = 15.8 centimetres, and DE=  3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

1)

When D is in between C and E .

.                   .           .

C                  D          E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

2)

When E is in between D and C.

.       .                .

D      E              C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

3 0
3 years ago
A ball is launched from a 682.276 meter tall platform. the equation for the ball's height h at time t seconds after launch is h(
blagie [28]

The maximum height the ball achieves before landing is 682.276 meters at t = 0.

<h3>What are maxima and minima?</h3>

Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.

We have a function:

h(t) = -4.9t² + 682.276

Which represents the ball's height h at time t seconds.

To find the maximum height first find the first derivative of the function and equate it to zero

h'(t) = -9.8t = 0

t = 0

Find second derivative:

h''(t) = -9.8

At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.

Maximum height at t = 0:

h(0) = 682.276 meters

Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.

Learn more about the maxima and minima here:

brainly.com/question/6422517

#SPJ1

4 0
2 years ago
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