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Usimov [2.4K]
3 years ago
12

Given that (6 3) is on the graph of f(x) find the corresponding point for the function f(-1/2x)

Mathematics
2 answers:
Vlada [557]3 years ago
6 0
\bf \begin{array}{rllll}
(6&,&3)&f(x)\\
x&&y\\\\
(-\frac{1}{2}x&,&3)&f(-\frac{1}{2}x)\\\\
(-\frac{1}{2}\cdot 6&,&3)\\\\
(-3&,&3)
\end{array}

keep in mind that, a negative coefficient to "x", will make the graph reflect over the y-axis.
nata0808 [166]3 years ago
4 0

Answer:

this answer is wrong on plato, trust me

Step-by-step explanation:


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Step-by-step explanation:

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2 years ago
In a bag of m&amp;m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&amp;m
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There are 5+6+4+3+2=20 m&m's in the bag.
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_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\&#10;=1140

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
P=&#10;\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}

The probability is 1/57.
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3 years ago
Solve for s<br><br> 1/3 s = 7
Vladimir79 [104]

Answer:

21

\frac{1}{3} s = 7 \\ s = 7 \times 3 \\ s = 21

8 0
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