Question

a 4-in hole has been bored through a 6-in cube. what is the approximate volume of the remaining solid? use 3.14 for pi

Answer 1

Answer:

141

Step-by-step explanation:

Answer 2

Answer:

The approximate volume of the remaining solid is $140.64\ in^{3}$

Step-by-step explanation:

we know that

The approximate volume is equal to the volume of the cube minus the volume of the cylinder

so

$V=b^{3}-\pi r^{2}h$

we have

$b=6\ in$

$r=4/2=2\ in$ -----> the radius is half the diameter

$h=6\ in$

substitute the values

$V=6^{3}-(3.14)(2^{2})(6)=140.64\ in^{3}$