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serg [7]
3 years ago
12

Evaluate 1 2/5 plus 3/8 need help ASAP

Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer: 1.775


Step-by-step explanation:





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Your total comes out to be $7.33 then the sales tax is 3% how much was the sales tax
Snowcat [4.5K]

Answer:

40.00

Step-by-step explanation:

4 0
3 years ago
How do you solve 0.8=6-2.5x
photoshop1234 [79]
X=2.08

To solve you need to first get x by itself. To do that you want to subtract 6 from both sides (get 6 away from x and put on other side) which will leave you with -5.2=-2.5x next isolate x by dividing -2.5 on both sides to then get 2.08=x
6 0
3 years ago
Read 2 more answers
Solve the system by graphing: y=-3x-3 and y=2x+2. Make sure you write your answer as an ordered pair: (x,y)
Rainbow [258]

Answer: (5, 12)

Step-by-step explanation:

Just graph the linear equations and find where they intersect.

Algebraically, you can set them equal to each other

-3x-3=2x+2

-x-3=2

-x=5

x=5

Plug x=5 to any equation

y=2(5)+2

y=12

3 0
3 years ago
Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AC is the only key for R, identify each of these FD's from the f
Goshia [24]

Given that R(ABCDE) is in Boyce-Codd normal form.

And AB is the only key for R.

Definition

A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is

a

Given that AB is the only key for R.

ABC E (Yes).

check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.

2) ACE B

(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.

ACE B

is

Boyce-Codd Normal Form not in BENE (NO)

3) ACDE → B           (NO)

check if is a super key. ACDE

As ACDE there is not any AB Tn ACDE. a super key.

ACDEB is not in BCNF.

4) BS → C → (NO)

As there is no AB in BC ~. B(→ not in BCNF

BC is not a super key.

5) ABDE (Yes).

Since AB is a key.

ABO TS a super key.

.. ABDE → E is in BCNF

Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.

1. ABC E

2. ACE B

3. ACDE B

4. BC C

5. ABD E

Learn more about Boyce-Codd Normal Form at

brainly.com/question/14299832

#SPJ4

6 0
1 year ago
Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.
Alona [7]

Answer:

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

\displaystyle T_ n = ar^{n-1}

Where <em>T</em>ₙ<em> </em>is the <em>n</em>th term, <em>a</em> is the initial term, and <em>r</em> is the common ratio.

We are given that the fifth term <em>T</em>₅ = 96 and the eighth term <em>T</em>₈ = 768. In other words:

\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}

Substitute and simplify:

\displaystyle 96 = ar^4 \text{ and } 768 = ar^7

We can rewrite the second equation as:

\displaystyle 768 = (ar^4) \cdot r^3

Substitute:

\displaystyle 768 = (96) r^3

Hence:

\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2

So, the common ratio <em>r</em> is two.

Using the first equation, we can solve for the initial term:

\displaystyle \begin{aligned} 96 &= ar^4 \\ ar^4 &= 96 \\ a(2)^4 &= 96 \\ 16a &= 96 \\ a &= 6 \end{aligned}

In conclusion, of the given geometric sequence, the first term <em>a</em> is 6 and its common ratio <em>r</em> is 2.

7 0
2 years ago
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