(2.0*10^4)(3.0*10^3) A. 6.0 * 10^7 B. 6.0 * 10^12 C. 6.0 * 10^5 D. 6.0 * 10^43

10. A 266-hp output is required for an engine. If there is a 5% loss of power, what amount of input

marta [7]

Answer:

Amount of input horsepower needed is 279.3 hp.

Step-by-step explanation:

if there is a loss of power of 5% the base horsepower will need to be increased by same percentage so that same amount of power can be delivered.

Now to calculate 5% of 266 hp, we can write

266 × $\frac{5}{100}$ = 13.3 hp

Now to deliver same amount of power we will have to add 5% of 266 hp to its actual power.

So real base power which is needed to deliver 266hp output even at a loss of 5% will be = (266+13.3) hp = 279.3 hp

To know more about horsepower and percentage problem:

brainly.com/question/24585630

7 0

3 years ago

ASNWER CORRECTLY AND YOU WILL GET 40 POINTS ALONG WITH BRAINLIEST

murzikaleks [220]

Answer: Angle ABC = 60, angle CBD = 120 and angle GFH = 60

Step-by-step explanation: Line ABD is parallel to line EFG. Line line CFH is a straight line that cuts across both parallel lines. Therefore, angle FBD and angle HFG are corresponding angles. That means angle FBD equals 3x. Also 3x plus 6X equals 180. That is,

3x + 6x = 180 {Sum of angles on a straight line equals 180}

9x = 180

Divide both sides of the equation by 9

x = 20.

That means angle 6x measures 6(20) and that is 120 degrees.

Also angle 3x measures 3(20) and that is 60 degrees.

Angle ABC + Angle CBD = 180 {Sum of angles on a straight line equals 180}

Angle ABC + 120 = 180

Angle ABC = 180 - 120

Angle ABC = 60

Also angle CBD equals 6x, and x = 20. Therefore angle CBD = 6 x 20

Angle CBD = 120.

And then, angle GFH = 3x, and x equals 20. Hence angle GFH = 60.

Therefore angle ABC = 60, angle CBD = 120 and angle GFH = 60.

7 0

3 years ago

Determine which of these sequences is an arithmetic sequence. Then determine the explicit formula that would be used to define t

vagabundo [1.1K]

6)

34, 43, 52, 61, ...

43-34 = 9; 52-43 = 9; 61-52 = 9

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 34

difference: d = 9

so the formula:

$a_n=a+d(n-1)\\\\a_n=34+9(n-1)\\\\a_n = 34+9n-9\\\\\underline{a_n=9n+25}$

7)

10, 6, 2, -2, ...

6-10 = -4; 2-6 = -4; -2-2 = -4

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 10

difference: d = -4

so the formula:

$a_n=a+d(n-1)\\\\a_n=10+(-4)(n-1)\\\\a_n = 10-4n+4\\\\\underline{a_n=-4n+14}$

8)

-3, -10, -17, -24, ...

-10-(-3) = -7; -17-(-10) = -7; -24-(-17) = -7

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = -3

difference: d = -7

so the formula:

$a_n=a+d(n-1)\\\\a_n=-3+(-7)(n-1)\\\\a_n =-3-4n+7\\\\\underline{a_n=-7n+4}$

9)

7, 8.5, 10, 11.5, ...

8.5-7 = 1.5; 10-8.5 = 1.5; 11.5-10 = 1.5

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 7

difference: d = 1.5

so the formula:

$a_n=a+d(n-1)\\\\a_n=7+1.5(n-1)\\\\a_n =7+1.5n-1.5\\\\\underline{a_n=1.5n+5.5}$

10)

30, 22¹/₂, 15, 7¹/₂, ...

22¹/₂-30 = -7¹/₂; 15-22¹/₂ = -7¹/₂; 7¹/₂-15 = -7¹/₂

The difference between one term and the next is a constant so it is arithmetic sequence

first term: a = 30

difference: d = -7¹/₂

so the formula:

$a_n=a+d(n-1)\\\\a_n=30+(-7\frac12)(n-1)\\\\a_n =30-7\frac12n+7\frac12\\\\ \underline{a_n=-7\frac12n+37\frac12}$

6 0

3 years ago

Compute the present value of $4800 paid in two years using the following discount rates: 8% in the first year and 7% in the seco

aleksandr82 [10.1K]

Answer:

Value 2 years from today 4%

Value one year from today5%

Present Value 6%

Step-by-step explanation:

5 0

3 years ago

What is 54 is 75% of

lukranit [14]

First put 54 over X in a fraction. 54/x
Then put 75 over 100. 75/100 
Then you cross multiply. 75(x)= 54(100) 
Simplify. 75x = 5400 
Divide. x=72 
Your answer is 72

8 0

3 years ago

Read 2 more answers