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jeka57 [31]
3 years ago
9

EASY AND BRAINLIEST!!!!

Mathematics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

6x-4y=15

Step-by-step explanation:

step 1

Find the slope of line L

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal

In this problem we have

2x + 3y = 5

Isolate the variable y

3y = -2x+5\\y=-(2/3)x+(5/3)

The slope of the given line is

m=-2/3

so

The slope of the Line L is

m=3/2

step 2

Find the x-intercept of the line

2x + 3y = 5

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

2x + 3(0) = 5\\x=5/2

The x-intercept is the point (5/2,0)

step 3

Find the equation of the line L

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=3/2\\point (5/2,0)

substitute

y-0=(3/2)(x-5/2)

y=(3/2)x-(15/4)

Convert to standard form

AX +By+C

where

A is a positive integer

B and C are integers

Multiply both sides by 4

4y=6x-15\\6x-4y=15

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Please help! I will give 50 points and brainliest.
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Answer:

Step-by-step explanation:

f * g = (x^2 + 3x - 4) (x+4)

open bracket

x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)

x³ +3x²-4x+x²+12x-16

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x³+4x²+8x-16 (domain is all real numbers.

f/g = (x^2 + 3x - 4)/(x+4)

factorising (x^2 + 3x - 4)

x²+4x-x_4

x(x+4) -1 (x+4)

(x+4)(x-1)

f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)

Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.

Hence I got x - 1, and x cannot equal -4

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2 years ago
If (2,0) is a solution of the linear equation 2x+3y=k,then the value of k is​
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Answer:

k = 4

Step-by-step explanation:

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Which of the following is equivalent to log base(25) 125?
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The solution to the problem is as follows:

x = log (25) (125) 

125 = 25^x 

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<span>
x = 3/2
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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2 years ago
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

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