Answer:
y=3/5X+5/6
Step-by-step explanation:
Y=ax+b
(-4;-3) (6:3)
-3=-4a+b
3=6a+b
3-6a=-3+4a
6=10a
a=6/10=3/5
b=5/6
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
option B
Step-by-step explanation:
First Quartile = 14
Plug in 30ft for L and 2310 for n so you will get 2310=7(30)(h)... h would equal 11ft
2 x 2 + 9x + 8 = 0
4 + 9x + 8 = 0
12 + 9x = 0 (subtract 12 from each side)
9x = -12 (divide by 9 on each side)
x = -12/9