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zhenek [66]
3 years ago
10

The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 101010 denarii per day to support 444

legionaries and 444 archers. It only costs 555 denarii per day to support 222 legionaries and 222 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier? Choose 1 answer:
Mathematics
1 answer:
givi [52]3 years ago
5 0

<u>the correct question is</u>

The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?

Let

x-------> the cost to support a legionary per day

y-------> the cost to support an archer per day

we know that

4x+4y=10 ---------> equation 1

2x+2y=5 ---------> equation 2

If you multiply equation 1 by 2

2*(2x+2y)=2*5-----------> 4x+4y=10

so

equation 1 and equation 2 are the same

The system has infinite solutions-------> Is a consistent dependent system

therefore

<u>the answer is</u>

We cannot solve for a unique cost for each soldier, because there are infinite solutions.

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The number -108.8 is a rational number

<h3>How to determine if the number is rational?</h3>

The number is given as:

negative 108.8

Rewrite properly as:

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Rational number have terminating decimals, and they can be represented as fractions.

The fraction equivalent of -108.8 is -1088/10

Hence, the number -108.8 is a rational number

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The given expression is \frac{-4}{5} \times \frac{3}{7}  \times \frac{15}{16}  \times (\frac{-14}{9}).

We need to simplify the given expression.

<h3>What is a rational number?</h3>

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

Now group the rational numbers (\frac{-4}{5}\times \frac{15}{16} ) \times (\frac{3}{7}\times (\frac{-14}{9}))

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Step-by-step explanation:

1/2bh

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