Answer:
width of the scale 10.8 inches
Step-by-step explanation:
This means the radius is 10 units. For it to be a circle, any point that lies on the circle is the same distance from the moving point to a fixed point (the centre). This distance is the radius.
As such, any other point that lies on the circle is 10 units from the centre as well.
Y=-3x for two slopes to be parallel they have to have the same slope but different y intercepts
Since bx does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting bx from both sides.
<span>-ay=-bx+2 </span>
<span>ax+by=3 </span>
<span>Divide each term in the equation by -1a. </span>
<span>y=(bx-2)/(a) </span>
<span>ax+by=3 </span>
<span>Divide each term in the numerator by the denominator. </span>
<span>y=(bx)/(a)-(2)/(a) </span>
<span>ax+by=3 </span>
<span>The equation is not linear, so the slope does not exist. </span>
<span>No slope can be found. </span>
<span>ax+by=3 </span>
<span>Since ax does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting ax from both sides. </span>
<span>No slope can be found. </span>
<span>by=-ax+3 </span>
<span>Remove the common factors that were cancelled out. </span>
<span>No slope can be found. </span>
<span>y=-(ax)/(b)+(3)/(b) </span>
<span>Divide each term in the equation by b. </span>
<span>No slope can be found. </span>
<span>y=(-ax+3)/(b) </span>
<span>Divide each term in the numerator by the denominator. </span>
<span>No slope can be found. </span>
<span>y=-(ax)/(b)+(3)/(b) </span>
<span>The equation is not linear, so the slope does not exist. </span>
<span>No slope can be found. </span>
<span>No slope can be found. </span>
<span>Compare the slopes (m) of the two equations. </span>
<span>m1=, m2= </span>
<span>The equations are parallel because the slopes of the two lines are equal.
</span>FROM YAHOO ANSWER
Answer: (10,-16)
Step-by-step explanation:
See the graph below.
Multiply both parts of the equation by 2:
Hence,
Multiply both parts of the equation by 2:
Hence,
