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Alex787 [66]
3 years ago
6

What is resource Management in Wireless Communication ? Explain its Advantages?

Computers and Technology
1 answer:
Brut [27]3 years ago
8 0

Answer:

Resource management is the system level transmission cellular networks and wireless communication.

Explanation:

Wireless communication is the process to continue to the address for faster response time,to the resource management.

Transmission is the provided by that more utilization and wireless resources available,and to discovered data.

Wireless communication system to demand the larger bandwidth and transmission using development to the system.

Wireless communication resources management the larger bandwidth and reliable transmission consumed all the system layer.

Resource management techniques tool are used in a preliminary concepts or mathematical tools,and average limited power battery.

Resource management are they necessary mathematical and fundamental tools are used in wireless communication.

Wireless communication in the provide that wireless industry in a wireless communication.

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4. Give four reasons why a laptop computer is more expensive than a desktop computer of the
kipiarov [429]
<h3>ANSWER:The main reason why laptops are more expensive than desktops is in the development costs to create hardware that is compact enough and at the same time meeting an expected level of performance.</h3>

<h3>And it’s not just performance that is a big challenge. It is also keeping the system cool enough that stability is maintained under most common usage conditions</h3>
3 0
2 years ago
I am buying a BluRay drive access time is 180ms and the other is 210ms(BD-ROM) whats does access time mean
kkurt [141]
It means how fast it can read the disk so if you want faster data transfer you would go for blurry if you really don't care go for the other one
6 0
2 years ago
Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

Reliability = 99.98\%

Individual Servers = 95\%

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

p = 95\%\\

It should be noted that probabilities always add up to 1;

So,

p + q = 1'

Subtract p from both sides

p - p + q = 1 - p

q = 1 - p

Substitute p = 95\%\\

q = 1 - 95\%

Convert % to fraction

q = 1 - \frac{95}{100}

Convert fraction to decimal

q = 1 - 0.95

q = 0.05

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

So,

p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

So,

p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

1 - q^n = 99.98\%

Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

0.0002 = q^n

Recall that q = 0.05

So, the expression becomes

0.0002 = 0.05^n

Take Log of both sides

Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

So,

Log(0.0002) = Log(0.05^n) becomes

Log(0.0002) = nLog(0.05)

Divide both sides by Log0.05

\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}

\frac{Log(0.0002)}{Log(0.05)} = n

n = \frac{Log(0.0002)}{Log(0.05)}

n = \frac{-3.69897000434}{-1.30102999566}

n = 2.84310893421

n = 3 (Approximated)

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0
3 years ago
The largest value (in hex) that can be loaded into Register A of HCS12 is (Points : 2) 0x8.
andrezito [222]

Answer:

0xFF.

Explanation:

The Register A of HSC12 is an 8-bit register.So the maximum value for 8 bit is 8 1's (11111111). So the decimal value for the maximum 8 bits is 255 but all the options given are in hexadecimal so among the given options only 0xFF has the value of 255 in decimal  F=(1111)₂.So two F's make 8 bits and their decimal value is 255.

7 0
3 years ago
How could the following line of code be shortened?
Alinara [238K]

Answer:

2

Explanation:

The second option is the only one that will work. The last would work but doesn't make the code any shorter.

8 0
1 year ago
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