Answer:
D the answer is D or c one of those 2
Answer:
Check the explanation
Explanation:
#include <bits/stdc++.h>
using namespace std;
class Rectangle{
public:
int length;
int breadth;
Rectangle(int l,int b){
length = l;
breadth = b;
}
int area(){
return length*breadth;
}
int perimeter(){
return 2*(length+breadth);
}
bool equals(Rectangle* r){
// They have the exact same length and width.
if (r->length == length && r->breadth == breadth)
return true;
// They have the same area
if (r->area() == area())
return true;
// They have the same perimeter
if (r->perimeter() == perimeter())
return true;
// They have the same shape-that is, they are similar.
if (r->length/length == r->breadth/breadth)
return true;
return false;
}
};
int main(){
Rectangle *r_1 = new Rectangle(6,3);
Rectangle *r_2 = new Rectangle(3,6);
cout << r_1->equals(r_2) << endl;
return 0;
}
Answer:
public class num9 {
public static void main(String[] args) {
int sum =0;
int num =5;
for(num =5; num<=500; num+=5){
System.out.println(num);
sum +=num;
}
System.out.println(sum);
}
}
Explanation:
- Declare and initialize the variables sum and num
- Use a for loop with the condition for(num =5; num<=500; num+=5) Since the loop will increment by 5 and run from 5 to 500
- Within the loop, add num to sum at each iteration
- Print all elements on seperate lines
- Outside the loop, print the final value of sum
Create a for loop
<em>The answer is : He must consult with a lawyer.
</em>
<em>Hacking is considered illegal and in other countries, it is punishable by law. Hacking is gaining unauthorized access to a network. Even when someone is giving you permission to do it, it is still wrong and illegal. Therefore, you must know of your rights and make all the party involved to signed an agreement to save yourself.</em>
Perhaps I’m being 5tup1d but I think your describing open source soft in general. Linux and a lot of periphery that runs on Linux is open source so it did play a large role being that it’s not proprietary like Windows and windows adjacent soft.
