Reduce the expression<span> by cancelling the </span><span>common factors</span><span>. </span><span><span>7<span>a^11</span><span>b^7/</span></span><span><span>a^3</span>b
</span></span>Reduce the expression<span> by cancelling the </span><span>common factors</span><span>. </span><span>7<span>a^8</span><span>b^7/</span></span>b
Reduce the expression<span> by cancelling the </span><span>common factors</span><span>. </span>7<span>a^8</span><span>b^<span>6
</span></span>28a^11 b^7 divided by 4a^3b simplified is 7a^8b^6
The answer is HL. HL is a theorem stating that if the hypotenuse and one leg are congruent to another pair of hypotenuse and leg then the triangles themselves are congruent. Hope this helps.
