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2 years ago

Factorise fully5ac - 10a2b + 30a

Mathematics

2 answers:

weqwewe [10]2 years ago

6 0

Answer:

5a(−2ab+c+6)

Step-by-step explanation:

Factor 5ac−10a2b+30a

−10a2b+5ac+30a

=5a(−2ab+c+6)

Answer:

5a(−2ab+c+6)

irga5000 [103]2 years ago

5 0

Answer:

5a(c-2ab+6)

Step-by-step explanation:

5a is in all three, then factorise

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246000 in scientific notation

atroni [7]

Answer:

2.46 x 10⁵

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

How do I solve number 10? I'm not sure if I did it right.

grandymaker [24]

No, you did it right

3 0

2 years ago

A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he

Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0

3 years ago

Udlinius<br>6x – 12 = 6(x - 2)

Sunny_sXe [5.5K]

If you distribute the 6(x-2) you would get 6x-12 so zero would equal zero

5 0

2 years ago

A cat gave birth to 3333 kittens who each had a different mass between 147147147147 and 159 g159\,\text{g}159g159, start text, g

harina [27]

Answer:

The correct option is (B).

Step-by-step explanation:

The median (m) is a measure of central tendency. To obtain the median, we assemble the data in arising order. If the data is odd, the median is the mid-value. If the data is even, the median is the arithmetic-mean of the two mid-values.

The mean of a data set is:

$\bar X=\frac{1}{n}\sum\limits^{n}_{x=0}{X}$

For the three kittens it is provided that the weights are in the range 147 g to 159 g.

So, the mean and median weight for the 3 kittens lies in the middle of this range.

Now a fourth kitten is born, with weight 57 g.

Now the range of the weight of 4 kittens is, 57 g to 159 g.

The mean is going to decrease as one more value is added to the data and the value is the least.

The median will also decrease because now the median will be mean of the 2nd and 3rd values.

But the mean would decrease more than the median because a smaller value is added to the data.

Thus, the correct option is (B).

5 0

2 years ago

Factorise fully5ac - 10a2b + 30a​

Factorise fully5ac - 10a2b + 30a