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3 years ago

What is the equation of the line ?

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

Answer:

The second one

Step-by-step explanation:

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A rectangle has an area of 20 cm^2. What will the area be if the rectangle tripled in size?

antoniya [11.8K]

Answer:

180 cm^2

Step-by-step explanation:

For similar figures the ratio of areas is the square of the ratio of linear dimensions.

We take "tripled in size" to mean that the linear dimensions of the larger rectangle are 3 times those of the smaller rectangle. That means the area of the larger rectangle will be 3² = 9 times the area of the smaller one.

Area = (3²)(20 cm²) = 180 cm² . . . . area after tripled in size

4 0

2 years ago

If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)]^2.<br><br> 1<br> 2<br> 9

stepladder [879]

I think that the answer would be 2 if I am right

5 0

3 years ago

Read 2 more answers

Using the digits 1, 2, 3, 4, 5, 6, 7, and 9, make 4 two-digit prime numbers. What is the sum of those four prime numbers?

mr_godi [17]

Answer:

13, 17, 19, and 23

Step-by-step explanation:

13+17+19+23=72

3 0

3 years ago

What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

$a=2\\b=7\\c=4$

substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

$x=\frac{-7\pm\sqrt{17}} {4}$

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

7 0

3 years ago

solve systems of equation. equation number 1: 9 x squared + 4 y squared equals 144. equation 2: x squared plus y squared equals

grigory [225]

$9x^{2} + 4y^{2} =144$
$x^{2} + y^{2}=24$

$9x^{2} + 4y^{2} =144$
$4x^{2} + 4y^{2}=96$
by the difference
5 $x^{2}$ =48
so x= $\sqrt{\frac{48}{5}}$ or x=- $\sqrt{\frac{48}{5}}$
and $y^{2}$ =24- $\frac{48}{5}$
then y= $\sqrt{\frac{72}{5}}$ or - $\sqrt{\frac{48}{5}}$

5 0

3 years ago