Answer:
Part A) 25
Part B) 225
Step-by-step explanation:
Part A
The slope of the graph gives us the mile per gallon of the car.
Recall that the slope of the graph is rise over run.

Therefore car gets 25 miles per gallon
Part B) Since we know the slope of the direct variation line, we substitute into y=kx to get:

To find the number of miles the car travels using 9 gallons, we substitute x=9 to get:

This gives us 225 miles
Answer:
10.9361
Step-by-step explanation:
The lower control limit for xbar chart is
xdoublebar-A2(Rbar)
We are given that A2=0.308.
xdoublebar=sumxbar/k
Rbar=sumR/k
xbar R
5.8 0.42
6.1 0.38
16.02 0.08
15.95 0.15
16.12 0.42
6.18 0.23
5.87 0.36
16.2 0.4
Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8
Xdoublebar=88.24/8
Xdoublebar=11.03
Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8
Rbar=2.44/8
Rbar=0.305
The lower control limit for the x-bar chart is
LCL=xdoublebar-A2(Rbar)
LCL=11.03-0.308*0.305
LCL=11.03-0.0939
LCL=10.9361
C
this is because i randomly guessed on ym test and got it right.
9514 1404 393
Answer:
-13/11
Step-by-step explanation:
Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...
![\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto%201%7D%5Cdfrac%7Bn%7D%7Bd%7D%3D%5Cdfrac%7Bn%27%7D%7Bd%27%7D%3D%5Cleft.%5Cdfrac%7B%5Cdfrac%7B4%7D%7B3%5Csqrt%5B3%5D%7B4x-3%7D%7D-%5Cdfrac%7B7%7D%7B2%5Csqrt%7B7x-6%7D%7D%7D%7B%5Cdfrac%7B5%7D%7B2%5Csqrt%7B5x-4%7D%7D-%5Cdfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B2x-1%7D%7D%7D%5Cright%7C_%7Bx%3D1%7D%3D%5Cdfrac%7B4%2F3-7%2F2%7D%7B5%2F2-2%2F3%7D%3D%5Cdfrac%7B8-21%7D%7B15-4%7D%5C%5C%5C%5C%3D%5Cboxed%7B-%5Cdfrac%7B13%7D%7B11%7D%7D)
The second choice than the fir2nd choice than the first choice for the second question