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Sphinxa [80]
2 years ago
15

If m∠ADB=(6x−4)° and m∠BDC=(4x+24)°, find the value of x such that ∠ADC is a right angle.

Mathematics
1 answer:
spayn [35]2 years ago
8 0

To make ∠ADC is a right angle, value of x will be 7.

From given figure, it is observed that Angle ADC is combination of two angles ADB and BDC.

                ∠ADC=∠ADB+∠BDC

Since, ∠ADC is right angle.

 So,  ∠ADC=90 degree

       90=∠ADB+∠BDC

     6x-4+4x+24=90\\     10x+20=90\\      10x=70\\       x=7

Learn more:

brainly.com/question/20158593

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Logan, a sales clerk in a book store, earns a base salary of $1,700 per month plus a commission of 5 percent on monthly sales ov
shepuryov [24]
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3 years ago
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slava [35]

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Step-by-step explanation:

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3 years ago
What expression must the center cell of the table below contain so that the sums of each row, each column, and each diagonal are
sergey [27]
Oh, I adore magic squares!

We need all rows to be equivalent, so try adding up the bottom (complete) row to get 7x-4x+3x=10x-4x=6x.

To solve the middle number, we have -2x+X+6x=6x, so X=2x.
To solve the top number, we have X+8x-3x=6x, so X=6x-8x+3x=x

Now check first column, 
x-2x+7x=6x   ok
Second column
8x+2x-4x=6x  ok
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3 years ago
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Sauron [17]

{3x}^{2}  - 5x =  - 8 \\  {3x}^{2}  - 5x + 8 = 0

This equation has the next form:

{ax}^{2}  + bx + c = 0

To find if the equation has two complex solutions we have to check if the discriminant is negative, as follows:

{b}^{2}  - 4ac \\ ( { - 5})^{2}  - 4 \: . \: 3 \: . \: 8 = 25 - 96 =  - 71 < 0

Then, the first case has two complex solutions.

In the second case,

{2x}^{2}  = 6x - 5 \\  {2x}^{2}  - 6x + 5 = 0

The discriminant in this case is:

( { - 6})^{2}  - 4 \: . \: 2 \: . \: 5 = 36 - 40 =  - 4 < 0

Then, the second case has two complex solutions.

In the third case,

12x =  {9x}^{2}  + 4 \\  { - 9x}^{2}  + 12x - 4 = 0

The discriminant in this case is:

{12}^{2}  - 4 \: . \: ( - 9) \: . \: ( - 4) = 144 - 144 = 0

Then, the third case has two real solutions.

In the fourth case,

{ - x}^{2}  - 10x = 34 \\  { - x}^{2} - 10x - 34 = 0

The discriminant in this case is:

( { - 10})^{2}  - 4 \: . \: ( - 1) \: . \: ( - 34) = 100 - 136 =  - 36 < 0

Then, the fourth case has two complex solutions.

7 0
2 years ago
Read 2 more answers
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