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lakkis [162]
4 years ago
15

Can someone please help??

Mathematics
1 answer:
Masja [62]4 years ago
5 0

Answer:

<h2>24 + 32p = 8(3 + 4p)</h2>

Step-by-step explanation:

24 = 8 · 3

32p = 8 · 4p

24 + 32p = 8 · 3 + 8 · 4p = 8 · (3 + 4p)

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We are interested in the dimensions of a certain square. A rectangle has a length of 5 units more than the side of the square an
JulijaS [17]
Lets consider the side of square be 'x' units
So as per data,
Length of rectangle is x+5
Breadth of rectangle is x/2

and also as per data, the areas of rectangle and square are equal.
Area of rectangle = Length * Breadth = (x+5)*x/2 = ( x^{2} +5x)/2 <- equation1
Area of square = Side* Side= x*x = x^{2}  <- equation2

As per given data, Equation1 and equation 2 are equal
so 
( x^{2} +5x)/2 = tex] x^{2} [/tex]  
x^{2} +5x = 2 x^{2}
2 x^{2} -  x^{2}   = 5x
x^{2}  = 5x
x = 5

So the side of square = 5 units  

For Square, both dimensions are equal.




4 0
3 years ago
Read 2 more answers
The profits for a large international bank were $2 234 569 000. What is this number rounded to the nearest billion?
Alex777 [14]
$2 234 569 000. is about two million
5 0
3 years ago
Read 2 more answers
Make x the subject of the formula<br> х<br> +12c = 5d<br> 63
dezoksy [38]
X=5db^3-2cb^3
Workup in photo below.
Good luck

7 0
3 years ago
Consider random samples of size 58 drawn from population A with proportion 0.77 and random samples of size 70 drawn from populat
fredd [130]

Answer:

Step-by-step explanation:

a) The formula for determining the standard error of the distribution of differences in sample proportions is expressed as

Standard error = √{(p1 - p2)/[(p1(1 - p1)/n1) + p2(1 - p2)/n2}

where

p1 = sample proportion of population 1

p2 = sample proportion of population 2

n1 = number of samples in population 1,

n2 = number of samples in population 2,

From the information given

p1 = 0.77

1 - p1 = 1 - 0.77 = 0.23

n1 = 58

p2 = 0.67

1 - p2 = 1 - 0.67 = 0.33

n2 = 70

Standard error = √{(0.77 - 0.67)/[(0.77)(0.23)/58) + (0.67)(0.33)/70}

= √0.1/(0.0031 + 0.0032)

= √1/0.0063

= 12.6

the standard error of the distribution of differences in sample proportions is 12.6

b) the sample sizes are large enough for the Central Limit Theorem to apply because it is greater than 30

8 0
3 years ago
Please show work.<br> 3. Solve the given inequality and graph the solution on a number line.
adelina 88 [10]

Answer:where’s the number line?

Step-by-step explanation:

8 0
3 years ago
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