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wariber [46]
2 years ago
9

In a group of 48 children there are twice as many boys as girls how many girls are they

Mathematics
1 answer:
Alexeev081 [22]2 years ago
3 0
Let x =  the number of boys.
Let y =  the number of girls.

There are 48 children, therefore
x + y = 48           (1)

There are twice as many boys as girls, therefore
x = 2y                 (2)

Substitute (2) into (1).
2y + y = 48
3y = 48
y = 48/3 = 16
x = 2y = 2*16 = 32

x=32, y = 16

Answer: 16 girls
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wlad13 [49]

Answer:

D

Step-by-step explanation:

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∠ BCD is an exterior angle of the triangle, thus

∠ BCD = 50° + 60 = 110° → D

6 0
2 years ago
Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or
soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

\lim_{x \to 3} f(x)

f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L

and the limit does not exist if

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Evaluate the one-sided limits.

The left-hand limit

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The right-hand limit

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8 0
3 years ago
PLEASE HELP ASAP!!
likoan [24]
The correct answer is D
6 0
2 years ago
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Answer:

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