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wariber [46]
3 years ago
9

In a group of 48 children there are twice as many boys as girls how many girls are they

Mathematics
1 answer:
Alexeev081 [22]3 years ago
3 0
Let x =  the number of boys.
Let y =  the number of girls.

There are 48 children, therefore
x + y = 48           (1)

There are twice as many boys as girls, therefore
x = 2y                 (2)

Substitute (2) into (1).
2y + y = 48
3y = 48
y = 48/3 = 16
x = 2y = 2*16 = 32

x=32, y = 16

Answer: 16 girls
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Let the required number be a.

Given,

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= > 10a + 7a^2 - 152 = 0

= > 7a^2 + 10a - 152 = 0

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