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Orlov [11]
3 years ago
11

Consider two countries' situations: Country A can produce either six automobile ror twelve movies with the same amount of resour

ces. Country B, using the same resources, can produce either five automobiles or eight movies. Using Ricardo' Theory of Comparative Advantage, determine which country would produce automobiles, which would produce movies, and the range of relative prices within which these product would trade?
Business
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

The theory of comparative advantage says that nations should yield and trade only those merchandises in which they have a reasonable advantage i.e. which they are specialize in.

To compute the comparative advantage of two nations A and B, let us first compute the opportunity cost of making movies and vehicles in each.

Country A:

Opportunity cost of making 1 automobile = 2 movies

Opportunity cost of making 1 movie = 1/2 automobile

Country B:

Opportunity cost of making 1 automobile = 8/5 movies

Opportunity cost of making 1 movie= 5/8 automobile

Since the prospect cost of making an automobile is lesser in Country B and the prospect cost of making movies is lesser in country A, thus Country A would make movies and country B would make automobiles.

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B. flexible work hours

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2 years ago
Shoreline Insurance deposited $27,000 in an account paying 4 compounded daily on April 2 and deposited an additional $4,200 in t
nydimaria [60]

Answer:

Balance on balance on July 1 is $31490.67

Explanation:

given data

deposited P =  $27,000

time = April 2  to May 12 = 40 days

rate = 4 % = 0.04

solution

we get here first compound amount that is express as

amount = P × (1+\frac{r}{n})^{nt}     ...................1

put her value

amount = 27000 ×  (1+\frac{0.04}{365})^{(365\times \frac{40}{365})}  

amount = $27118.60

and

now we add here $4,200 in $27118.60 that will be

new principal P = $31318.60

and time t = 12 may to July 1 = 50 days

we get here amount that is put value in equation 1 we get

amount = $31318.60 ×  (1+\frac{0.04}{365})^{(365\times \frac{50}{365})}

solve it we get

amount = $31490.67

so that balance on balance on July 1 is $31490.67

5 0
3 years ago
Until recently, hamburgers at the city sports arena cost $ 2.50 each. The food concessionaire sold an average of 1750 hamburgers
Artyom0805 [142]

Answer:

  (A) p = -0.002x +6; 0 ≤ x ≤ 3000

  (B) R(x) = x(6 -0.002x); 0 ≤ x ≤ 3000

  (C) C(x) = 1.44x +1903

  (D) (550, 2695), (1730, 4394.20)

  (E) P(x) = -0.002x^2 +4.56x -1903

  (F) increasing at $2.16 per hamburger

Explanation:

(A) The two-point form of the equation for a line can be used.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

The two points we have are ...

  (x, p) = {(1750, 2.50), (1450, 3.10)}

so the equation is ...

  p = (3.10 -2.50)/(1450 -1750)/(x -1750) +2.50

  p = 0.6/-300(x -1750) +2.50

  p = -0.002x +6

The domain of this function is where x and p are greater than 0. That will be for ...

  0 ≤ x ≤ 3000

__

(B) Revenue is the product of burgers sold (x) and their price (p).

  R(x) = xp

  R(x) = x(6 -0.002x)

The domain of R(x) is 0 ≤ x ≤ 3000. This is the same as the domain of p(x).

___

(C) The cost function is the sum of fixed costs and variable costs:

  C(x) = 1.44x +1903

__

(D) See the attachment for a graph of cost and revenue. The break-even points are (x, revenue) = (550, 2695), (1730, 4394.20).

__

(E) Profit is the difference between revenue and cost.

  P(x) = R(x) - C(x) = x(6 -0.002x) -(1.44x +1903)

  P(x) = -0.002x^2 +4.56x -1903

__

(F) The marginal profit is the derivative of the profit function:

  P'(x) = -0.004x +4.56

  P'(600) = -0.004(600) +4.56 = -2.40 +4.56 = 2.16

At a production level of 600, the profit is increasing at a rate of $2.16 per hamburger.

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Explanation:

To list out the responsibilities the following might be helpful:

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To list out the skill and attitude:

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Answer:

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