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Murljashka [212]
3 years ago
6

Please help me with this problem !!

Mathematics
1 answer:
jasenka [17]3 years ago
7 0
Since a pentagon can be divided into 3 triangles and each triangle has interior angles equal to 180, 3 * 80 = 540.  All the interior angles of a pentagon add up to equal 540.  We are given the first one of 140.  That is where we will start.  The angle right next to that one to the right is supplementary to the 60 degree exterior angle, so the measure of the next interior angle is 180 - 60 = 120.  The angle next to that in line has an exterior angle measure of 84.  So 180 - 84 = 96.   Next in line is an angle with an exterior measure of 68, so 180 - 68 = 112. Adding up all the bolded angle measures gives us that the last interior angle measures 72.  But we want the measure of x which is an exterior angle.  72 and x are supplementary, therefore, 180 - 72 = x.  x = 108.  Choice B.
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109+(2x-3)+x+(x+32)+164+x+(x-7)=740 find x
tatyana61 [14]

Answer:

x = \frac{445}{6} or 74\frac{1}{6}

Step-by-step explanation:

5 0
3 years ago
1500(0.04)(3)=1500(0.04)(3)=
san4es73 [151]
1500(0.04) = 60
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4 0
3 years ago
a family of 5 children share the bread as follows three-quarters of the bread is shared among 2 children and the rest share the
Gelneren [198K]

Answer:

\frac{1}{12}

Step-by-step explanation:

\frac{4}{4} -\frac{3}{4} =\frac{1}{4} \\\\\frac{1}{4} divided by3=\frac{1}{12}

8 0
3 years ago
Read 2 more answers
What is the ratio of the area of the inner square to the area of the outer square?
Nadusha1986 [10]

The area of ​​the inner square to the area of ​​the outer square ratio is:  \frac{(a-b)^2+b^2}{a^2}

Given a figure in which an inner square is inscribed inside the outer square.

The area of ​​a square is the product of the two sides of the square. Also known as side square.

Firstly, we will find the side of the inner square by finding the distance between the points (0,b) and (a-b,0)

S₁=√(a-b-0)²+(b-0)²

S₁=√(a-b)²+b²

Now, we will find the area of the inner square, we get

The area of the inner square=(side)²

A₁=(S₁)²

A₁=(√(a-b)²+b²)²

A₁=(a-b)²+b²square cm.

Further, we will find the side of the outer square by finding the distance between the points (0,0) and (a,0).

S₂=√(a-0)²+0²

S₂=√a²

S₂=a

Furthermore, we will find the area of the outer square, we get

The area of the outer square=(side)²

A₂=(S₂)²

A₂=a² square cm.

Hence, the area of the inner square to the area of the outer square ratio is \frac{(a-b)^2+b^2}{a^2}.

Learn more about the area of the square from here brainly.com/question/4102299

#SPJ4

5 0
2 years ago
Evaluate the expression for x=5, y=-3 and z=7<br> (x2 – z) (22+5)
Contact [7]

Answer:

81

Step-by-step explanation:

Hello! Thanks for letting me answer your question! If you have any more questions feel free to ask me! If not, Have a WONDERFUL day and Please don't forget to consider making me Brainliest on your question today!

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