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olga_2 [115]
3 years ago
15

What is the length of segment RS

Mathematics
2 answers:
inessss [21]3 years ago
6 0

Answer: 13 units


Step-by-step explanation:

The length of line segment AB with points A(x_1,y_1)\ and\ B(x_2,y_2) is given by distance formula as :

\text{AB}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Now, the length of line segment RS with points R(-4,-3)\ and\ S(1,9) is given by distance formula as :

\text{RS}=\sqrt{(1-(-4))^2+(9-(-3))^2}\\\Rightarrow\ RS=\sqrt{(5)^2+(12)^2}\\\Rightarrow\ RS=\sqrt{25+144}=\sqrt{169}\\\Rightarrow\ RS=13

Hence, the length of segment RS= 13 units

Assoli18 [71]3 years ago
5 0
The length of segment RS must be 13 units.

To find this, you can make a right triangle by connecting points R and S at a common point to form a right angle. The segments made would be 5 units and 12 units long. Using the Pythagorean Theorem, the segment RS must be 13 units.
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Step-by-step explanation:

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Nine cars (3 Pontiacs [labeled 1-3], 4 Fords [labeled 4-7], and 2 Chevrolet's [labeled 8-9]) are divided into 3 groups for car r
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Answer:

The number of different ways to arrange the 9 cars is 362,880.

Step-by-step explanation:

There are a total of 9 cars.

These 9 cars are to divided among 3 racing groups.

The condition applied is that there should be 3 cars in each group.

Use permutation to determine the total number of arrangements of the cars.

  • For group 1:

       There are 9 cars and 3 to be allotted to group 1.

       This can happen in ^9P_{3} ways.

        That is, ^9P_{3}=\frac{9!}{(9-3)!} =504 ways.

  • For group 2:

       There are remaining 6 cars and 3 to be allotted to group 2.

       This can happen in ^6P_{3} ways.

        That is, ^6P_{3}=\frac{6!}{(6-3)!} =120 ways.

  • For group 3:

       There are remaining 3 cars and 3 to be allotted to group 3.

       This can happen in ^3P_{3} ways.

        That is, ^3P_{3}=\frac{3!}{(3-3)!} =6 ways.

The total number of ways to arrange the 9 cars is: ^9P_{3}\times ^6P_{3}\times ^3P_{3}=504\times120\times6=362880

Thus, the number of different ways to arrange the 9 cars is 362,880.

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