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joja [24]
4 years ago
9

You need a loan of $135,000 to buy a home. Calculate your monthly payment and total closing costs for each choice below. Briefly

discuss how you would decide between the two loans. Choice 1: 15 year fixed rate at 4% with closing costs of $2700 and no points. Choice 2: 15 year fixed rate at 3.5% with closing costs of $2700 and 5 points. What’s the monthly payment for choices 1 and 2? What are the total closing costs for choices 1 and 2?
Mathematics
1 answer:
Ahat [919]4 years ago
6 0
You need to multiply the four numbers and then takeway
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A data set includes weights of garbage discarded in one week from 62 different households. The paired weights of paper and glass
lara [203]

Answer:

Because the absolute value of the test statistic is <u>less than</u> the positive critical value, there <u>is not</u> enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.

Step-by-step explanation:

The correlation​ matrix provided is:

Variables    Paper     Glass

  Paper           1         0.1853

 Glass        0.1853         1

Te hypothesis for the test is:

<em>H</em>₀: <em>ρ</em> = 0 vs. <em>H</em>₀: <em>ρ</em> ≠ 0

The test statistic is:

<em>r</em> = 0.1853 ≈ 0.185

As the alternate hypothesis does not specifies the direction of the test, the test is two tailed.

The critical value for the two-tailed test is:

r_{\alpha/2, (n-2)}=r_{0.05/2, (62-2)}=r_{0.05/2, 60}=0.250

The conclusion is:

Because the absolute value of the test statistic is <u>less than</u> the positive critical value, there <u>is not</u> enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.

6 0
3 years ago
A bacteria population is 3000 at time t = 0 and its rate of growth is 1000 · 8t bacteria per hour after t hours.
julia-pushkina [17]
P=3000x e^( 1000 x 8t )is the function
t is time, so "after a hour" means that the t is 1.
The problem is asking for the population, which is P
Substitute t for 1 and you obtain:
P= 3000 x e^(1000 x 8 x 1)
P=3000e^8000
4 0
3 years ago
What’s the numerator for the following rational expression please I need help quick taking test currently
bulgar [2K]

Answer:

Well, the most reasonable explanation would be j+8 or 8+j

4 0
3 years ago
Simplify (4/5)^-2 . Show your work!
jarptica [38.1K]

Answer:

\frac{25}{16}

Step-by-step explanation:

Apply exponent rule: x^{-y}=\frac{1}{x^y}

(\frac{4}{5}) ^{-2}=\frac{1}{\left(\frac{4}{5}\right)^2}=\frac{1}{\frac{16}{25}}=\frac{25}{16}

5 0
3 years ago
Laser scanning for fish volume estimation. engineers design tanks for rearing commercial fish to minimize both the use of natura
AVprozaik [17]

Answer:

The 99% confidence interval would be given by (196.2;283.8)

We are 99% condident that the true mean is between 196.2 and 283.8  

We need to assume that the data comes from a random sample and we need to assume that the distribution of the data is normal.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=240 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=15 represent the sample standard deviation

n=4 represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=4-1=3

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,3)".And we see that t_{\alpha/2}=5.84

Now we have everything in order to replace into formula (1):

240-5.84\frac{15}{\sqrt{4}}=196.2    

240+5.84\frac{15}{\sqrt{4}}=283.8

So on this case the 99% confidence interval would be given by (196.2;283.8)    

We are 99% condident that the true mean is between 196.2 and 283.8

What assumption about the data is necessary for the inference derived from the analysis to be valid?

We need to assume that the data comes from a random sample and we need to assume that the distribution of the data is normal.

4 0
3 years ago
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