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kipiarov [429]
4 years ago
6

Will give brainliest to correct answer!

Mathematics
1 answer:
vesna_86 [32]4 years ago
6 0
The answer is A. (0, 9) 

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On an airplane there are two seats on the left side in each row and three seats on the right side there are 90 seats on the righ
Anuta_ua [19.1K]
<em><u>The correct answer is 60 seats on the left side</u></em>, but you might also want to know how I got that answer . . .

Let's say, n = number of rows

Since we know the airplane has an equal number of rows on the right side as it does on the left side, then we can mathematically show that:

number of sears on the right side = 3n = 90 seats
number of sears on the left side = 2n = ? seats

3n = 90

n = number of rows = 90/3 = 30 rows

Thus:

2n = 2(30) = <u><em>60 seats on the left side</em></u>

<em>as for how many seats all together, just add . . 90 + 60 = 150 seats total</em>

3 0
3 years ago
If 6 chocolates cost $0.93, how much do 22 chocolates cost?
ozzi

I would be $3.41 first you figure out how much one cost by dividing 0.93 by 6 then you multiply your answer by 22

 

6 0
4 years ago
A 6,000​-liter cistern is empty when water begins flowing into it​ (at t = ​0) at a rate​ (in L/min) given by Q`(t) = 9 √t, wher
lorasvet [3.4K]

Answer:

a) 6,455 L

b) V(t) = (18/3) * t^(1.5)

Step-by-step explanation:

Part a

Integrating the given relation from t = 0 to t= 105 mins

V = \int {9 * \sqrt{t} } \, dt\\V = {\frac{9*2}{3}*t^(1.5) = \frac{18}{3}*t^(1.5)\\\\V = \frac{18}{3}*105^(1.5)\\\\\\V = 6,455L

Part b

V(t) = \frac{18}{3} * t^(1.5) + C\\Since V = 0 @ t = 0 ; hence, C = 0\\\\V(t) = \frac{18}{3} * t^(1.5)

6 0
3 years ago
What is the variable to 3x-5 ​
Vlad1618 [11]

Answer:

3 (2x + 3) + 11 = –2 (2x - 6) - 18

6 0
3 years ago
Read 2 more answers
The line graph shows the time spent by people visiting the
kari74 [83]

Answer:

Option (B)

Step-by-step explanation:

Average waiting time in the month of October = 20 minutes

Average waiting time in the month of November = 30 minutes

Average waiting time in the month of December = 60 minutes

Average waiting time in the month of January = 40 minutes

Average waiting time in the month of February = 10 minutes

Average waiting time in the month of March = 10 minutes

Average waiting time in the month of April = 30 minutes

Average waiting time in the month of May = 40 minutes

Average waiting time in the month of June = 20 minutes

Total waiting period from October to June = 20 + 30 + 60 + 40 + 10 + 10 + 30 + 40 + 20 = 260

Average waiting period = \frac{260}{9}

                                       = 28.89

                                       ≈ 29 minutes

Option (B) is the answer.

5 0
3 years ago
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