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vesna_86 [32]
3 years ago
7

On an airplane there are two seats on the left side in each row and three seats on the right side there are 90 seats on the righ

t side of the plane how many seats are on the left side of the airplane

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
<em><u>The correct answer is 60 seats on the left side</u></em>, but you might also want to know how I got that answer . . .

Let's say, n = number of rows

Since we know the airplane has an equal number of rows on the right side as it does on the left side, then we can mathematically show that:

number of sears on the right side = 3n = 90 seats
number of sears on the left side = 2n = ? seats

3n = 90

n = number of rows = 90/3 = 30 rows

Thus:

2n = 2(30) = <u><em>60 seats on the left side</em></u>

<em>as for how many seats all together, just add . . 90 + 60 = 150 seats total</em>

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where A(t) is the amount after the depreciation occurs, r is the interest rate in decimal form, and t is the time in years.  We know the initial amount (70,000) and the interest rate (.04), but we need to figure out what t is.  If the car was bought in 2006 and we want its value in 2018, a total o 12 years has gone by.  Therefore, our equation becomes:

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Make 'h' as the subject. Remember to rationalize the denominator while solving.
Sliva [168]

Hello there BeGuiLE !

To solve your question,  we must first bring 'h' to one side of the equation.  Let's bring all the terms with the variable 'h' to the left side of the equation. So,
\large{\sf\sqrt{ 3  }  h =  1.6+h}
→ \large{\sf\sqrt{3}h-h=1.6 }

Now, let's combine the 2 terms containing the variable 'h'.
\large{\sf\sqrt{3}h-h=1.6 }
→ \large{\sf\left(\sqrt{3}-1\right)h=1.6 }

Now, we need to leave the variable 'h' alone in the left side of the equation & bring (√3 + 1) to the other side of the equation. This is done in order to make 'h' as the subject of the equation. So, we'll get it as,
\large{\sf\left(\sqrt{3}-1\right)h=1.6 }
→ \large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }

Now, let's rationalize it. Rationalizing is a process where we move the root from the denominator of a fraction to the numerator for easier calculation. So,
\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{(\sqrt{3}-1 )(\sqrt{3}+1}) }
Now, use the algebraic identity, (a + b)(a - b) = a² - b²
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{3-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{2} }
→ \boxed{\large{\sf\:h=0.8(\sqrt{3}+1)}}

Now, we've made 'h' as the subject of the equation. If you want to solve it more, then,
\large{\sf\:h=0.8(\sqrt{3}+1)}
Take √3 as 1.73 (approx. value up to 2 decimal places)
→ \large{\sf\:h=0.8(1.73+1)}
→ \large{\sf\:h=0.8(2.73)}
→ \boxed{\boxed{\huge{\bf{\:h=2.184 \: (approx.)}}}}

I hope this will help you.

Please refer to the attached image if the explanation shows some error.

_______

Check out more links which will help you understand the topic better :

■ brainly.com/question/21406377

■ brainly.com/question/696184

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\mathfrak{Lucazz}


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