Answer:
x = 1; y = 1; z = 0
Step-by-step explanation:
First problem:
First equation minus second equation: 3y + 2z = 3 Eq. A
Second equation plus third equation: 2y + 4z = 2 Eq. B
-2 times Eq. A plus Eq. B: -4y = -4
y = 1
Substitute y = 1 in Eq. A: 3 + 2z = 3
2z = 0
z = 0
Substitute z = 0 and y = 1 in original first equation:
-2x + 2 + 0 = 0
-2x = -2
x = 1
Answer: x = 1; y = 1; z = 0
Answer:
Step-by-step explanation:
Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola
the parabola is open down with vertex at (0,2)
We can find that the rectangle also will be symmetrical about y axis.
Let the vertices on x axis by (p,0) and (-p,0)
Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation
Now width =
Area = l*w =
Use derivative test
I derivative =
II derivative =
Equate I derivative to 0 and consider positive value only since we want maximum
p =
Thus width=
Length =
Width =
I think the correct answer is C. because each if forming a right triangle when you trace it.
If i'm correct brainliest please
Answer:
1/2
Step-by-step explanation:
Answer:
Hi, there your answer is y=3x+4
Step-by-step explanation:
I did rise over run