Using the Pythagorean Theorem, we can tell that there is 10 units between the two points.
Since we are solving for h, the equation:
V = πr²h
...divides πr² to the other side. Thus, it becomes....
= h
Which can be rewritten as....
h =
By either long or synthetic division, it's easy to show that
The quartic will be exactly divisible by
when the numerator of the remainder term vanishes, or for those values of
such that
I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.
Answer:
Area of regular pentagon is 238.95 square inches.
Step-by-step explanation:
Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.
we know a regular polygon divides into 5 congruent triangles.
Side of pentagon i.e base of one triangle is 11.8 inches.
Also, distance from center to middle of side which is height of triangle is 8.1 inches.
Area of 1 triangle=
=
= 47.79 sq inches.
Area of regular pentagon=area of 5 congruent triangles= =238.95 sq inches.
Answer:
Step-by-step explanation:
here is a solution :