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vivado [14]
4 years ago
15

Does the temperature 0 degrees mean the same thing on both scales.

Mathematics
1 answer:
Vera_Pavlovna [14]4 years ago
3 0
No 0c is the same as 32f not 0f
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Five busses are needed to transport 300 students. How many students can 7 busses transport?
FinnZ [79.3K]

Answer:

420 students

Step-by-step explanation: I first did 300/5 which got me 60, meaning that one bus could transport 60 students. Then you do 60*7 (60 is how many students on each bus, and 7 is how many buses there are) and get 420 students on 7 buses.

3 0
3 years ago
Read 2 more answers
How many times does 0.5 go into 10.80?
barxatty [35]

Answer:

21.6

Step-by-step explanation:

10.80/0.5=21.6

5 0
3 years ago
Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3
Serhud [2]

Answer:

e^{3t}(2t+5t^{2})

Step-by-step explanation:

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem:L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]

Separate the fraction in a sum:

e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])

The formula for this is:

L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}

Modify the expression to match the formula.

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])

Solve

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )

6 0
3 years ago
What is the value of x!? thanks!!!
Phantasy [73]
I have no clue. i’m only here bc i need to ask a question but ic gl
3 0
3 years ago
Read 2 more answers
I need the answer asap, will mark brainliest
tino4ka555 [31]

Answer:

I would say (-1,1)

Step-by-step explanation:

hope this helpsn

6 0
3 years ago
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