I need the answer asap, will mark brainliest

The lines shown below are perpendicular. If the green line has a slope of 2/5 what is the slope of the red line

Ksenya-84 [330]

In this item, we are not given with the figure but knowing that these lines ought to be perpendicular then we will be able to derive the relationship between the slopes of the line.

The slopes of the perpendicular line are the negative reciprocals of one another. If we represent the slopes of the lines as m₁ and m₂, the relationship can be written in the form,
(m₁)(m₂) = -1

We are given with one of the slopes. To determine the value of the second slope then,
m₂ = -1/m₁
m₂ = -1/(2/5)
m₂ = -5/2

<em>ANSWER: m₂ = -5/2</em>

6 0

3 years ago

How would you scale down by a factor of 1/10?

slavikrds [6]

Answer:

See example below.

Step-by-step explanation:

To scale down by a factor of 1/10, multiply the side length or distance by 1/10.

Example:

If the distance was 5 then 5*1/10 = 5/10 = 1/2 is the scaled down version.

6 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Three consecutive integers have a sum of 56. what are the three integers

denis23 [38]

Answer:

impossible

Step-by-step explanation:

X + X + 1 + X + 2 = 56. To solve for X, you first add the integers together and the X variables together. Then you subtract 3 from each side, followed by dividing by 3 on each side. ...

3X + 3 = 56. 3X + 3 - 3 = 56 - 3.

3X = 53. 3X/3 = 53/3.

X = 17 2/3. Since 17 2/3 is not an integer, there is no true answer to this problem.

8 0

3 years ago

Rewrite y = -(x + 2)2 – 5 in standard form.

xenn [34]

Answer:

y = - x² - 4x - 9

Step-by-step explanation:

Given

y = - (x + 2)² - 5 ← expand (x + 2)² using FOIL

= - (x² + 4x + 4) - 5 ← distribute parenthesis by - 1

= - x² - 4x - 4 - 5 ← collect like terms

= - x² - 4x - 9 ← in standard form

8 0

3 years ago