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3 years ago

Write 658.129 in expanded form?

1 answer:

8 0

Write 658.129 in expanded form.

600 + 50 + 8 + .1 + .02 + .009

600 + 50 + 8 + .1 + .02 + .009 = 658.129

658.129 in expanded form is
600 + 50 + 8 + .1 + .02 + .009.

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Solve the equation for x. 2 3 x −1 9 x + 5 = 20 x =

zubka84 [21]

Answer:

5/2

Step-by-step explanation:

23x-19x+5=2x

23x-19x-2x=5

2x/2=5/2

x=5/2

3 0

3 years ago

Read 2 more answers

There are 24 pairs of shoes in a closet. If 25% of the pairs of shoes are black, how many pairs are NOT black?

Elden [556K]

25%=0.25
24*0.25=6
24-6=18
18 pairs are not black

7 0

3 years ago

Read 2 more answers

You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)

Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, $v_1$ = = 20 m./s

Velocity of the truck 2, $v_2$ = 35 m./s

1. Kinetic energy of the truck 1: $\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules$

Kinetic energy of the truck 2: $\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules$

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = $mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules$

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0

3 years ago

Lionel’s work crew packages 150,087 bottles of water every day. If the crew works 5 days, how many bottles can they package in a

yawa3891 [41]

Answer:

im sorry this might not be exactly correct but the answer can be 1,050,609

Step-by-step explanation:

1 week= 7 days so

150,087 × 7 = 1,050,609

‍♀️

3 0

2 years ago

In a sample of n = 6 scores, 5 of the scores are each above the mean by one point. Where is the 6th score located relative to th

den301095 [7]

The mean of a dataset is the sum of all data elements divided by the count of the elements.

The location of the 6th score relative to the mean is 5 points below the mean

Let:

$\bar x \to$ Mean

$a \to$ 5 scores

$b \to$ 6th scores

Given that:

$n = 6$

The 5 scores that are 1 above the mean implies that:

$a = \bar x + 1$

The mean of a dataset is calculated using:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x =\frac{5a + b}{6}$

$\bar x =\frac{5(\bar x + 1) + b}{6}$

Open brackets

$\bar x =\frac{5\bar x + 5 + b}{6}$

Multiply both sides by 6

$6\bar x =5\bar x + 5 + b$

Make b the subject

$b = 6\bar x -5\bar x - 5$

$b = \bar x - 5$

This means that the 6th score is 5 points below the mean