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Semenov [28]
3 years ago
14

Ahmed and Karnia are building scenery of the Egyptian pyramids out of plywood for a community play. They pyramids are represente

d by triangles on a rectangular base
A.) how many square feet of plywood is in the scenery? Show your work

B.) the pyramids (the triangles) will be painted gray, and the base(the rectangle) will be painted black. How much of each paint color will they use, if one quart covers 45 square feet? Only one side of the model needs to be painted, but two coats of paint will be needed. Show your work. Round to the nearest hundredth of a square foot

Mathematics
1 answer:
Arlecino [84]3 years ago
5 0
A.)
 
The first thing we must do for this case is to find the area of ​​the complete figure.
 We have then:
 Triangle 1:
 A1 = (1/2) * (1.5) * (1)
 A1 = 0.75 feet ^ 2
 Triangle 2:
 A2 = (1/2) * (1.5) * (2)
 A2 = 1.5 feet ^ 2
 Triangle 3:
 A3 = (1/2) * (0.75) * (1)
 A3 = 0.375 feet ^ 2
 Rectangle:
 A4 = (5) * (0.75)
 A4 = 3.75 feet ^ 2
 Adding the areas we have:
 A = A1 + A2 + A3 + A4
 A = 0.75 + 1.5 + 0.375 + 3.75
 A = 6.375 feet ^ 2
 Answer:
 there are 6,375 feet ^ 2 of plywood in the scenery

 B.)
 
Triangles:
 A = A1 + A2 + A3
 A = 0.75 + 1.5 + 0.375
 A = 2,625 feet ^ 2
 Two layers of paint:
 A = 5.25 feet ^ 2 <45 feet ^ 2
 Rectangle:
 A = 3.75 feet ^ 2
 Two layers of paint:
 A = 7.5 feet ^ 2 <45 feet ^ 2
 Answer:
 
One quart of each color is needed.
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Answer:  The circumference is:  " 8.87 square units " .
_________________________________________________
Explanation:
_____________________________________
Note the following:
________________________________
Area of a circle:  A = π r² = 25 units² ; 
 
Circumference of a circle:  C = π*d = 2πr
____________________________________
  If we can solve for "r" ("radius", we can solve for the "Circumference, "C") ;
__________________________________
   A = π r² = 25 ;

    C = 2 * π *r
 
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________________________
 We know that:  " π * r * r = 25" ; 

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      2*{ π * r * r = 25} ;
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To get:  2 * π * r * r = 25 ; 

Note:  "C = 2* π * r ; 

So,  "(2 * π * r) * r = 25 " ; 

We want to solve for "C" ; so replace the "(2 * π * r) " ; with "C" ;
 
          C * r = 25 ; 
______________________________
Divide EACH SIDE of the equation by "r" ; to isolate "C" on one side of the equation:
________________________________
   (C * r) / r  =  25 / r   ;

to get:    C  =  25 / r ;  
____________________________________
Now, we need to find the value for "r" (the radius);
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We know that:  
____________________________________ 
   π * r² = 25 ;
____________________________________
Divide each side of the equation by "π"; to isolate "r² " on one side of the equation;
____________________________________
   (π * r²) / π  =  25 / π ;

To get:  
___________________________________________________
   r²  =  25/π  ;  Let us use "3.14" as an approximation for "π" ;
___________________________________________________
   r²  =  25 / (3.14) ; 
  
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Take the "positive" square root of EACH side of the equation; 
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_____________________________________________

   +√(r²) = +√(7.9617834394904459) ; 
_____________________________________________
to get:
_____________________________________________
      r  =  2.8216632399155016635 ;  
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The answer is:  "8.87 square units" .
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