Answer:
So to maximize profit 24 downhill and 20 cross country shouldbe produced
Step-by-step explanation:
Let X be the number of downhill skis and Y the number of cross country skis.
Time required for manufacturing and finishing each ski are: manufacturing time per ski, downhill 2.5 hours, cross country 1.5 hours
Finishing time per ski: downhill 0.5 hours, cross country 1.5 hours.
Total manufacturing time taken = (2.5) x+ (1.5+) y = 2.5x+1.5y≤90
total finishing time taken = 0.5x+1.5 y≤42
Profit function
Z = 50x+50y
Objective is to maximize Z
Solving the two equations we get intersecting point is
(x,y) = (24,20)
In the feasible region corner points are (0.28) (36,0)
Profit for these points are
i) 2200 for (24,20)
ii) 1400 for (0,28)
iii) 1800 for (36,0)
So to maximize profit 24 downhill and 20 cross country shouldbe produced.
Answer:
3. 10000
Step-by-step explanation:
Given the following :
Number of gumball cartons = 3
Number of boxes per carton = 100
Number of gumballs per box = 100
The number of gumballs can be expressed in the form : (a. 10) ; where ; a = prime number ; b = whole number
Values of a and b?
Total number of gumballs :
Number of carton × number of boxes per carton × number of gumballs per box
3 × 100 × 100
Hence, writing the expression in the form: a. 10
a. 10 = 3 × 10000
258 cubic inches
Since the boxes are kind of on their own—>
First box: 7*2*12 = 168
Second box: 5*2*9=90
168+90 = 258
Answer:

Step-by-step explanation:
We need to rationalize the denominator of
. For rationalizing we multiply the equation by 
So, solving

Answer:
9.5
Step-by-step explanation: