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Mariulka [41]
4 years ago
9

This graph shows a proportional relationship.

Mathematics
1 answer:
ASHA 777 [7]4 years ago
8 0

Answer:

k=\frac{3}{2}

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem we have the point (1/4,3/8)

The constant of proportionality k is equal to

k=\frac{y}{x}

substitute the value of y and the value of x of the given ordered pair

k=\frac{3}{8}:\frac{1}{4}

Multiply in cross

k=\frac{3*4}{8*1}=\frac{12}{8}

Simplify

k=\frac{3}{2}

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Answer:

a. y(t) = 0

Step-by-step explanation:

There are two axis on the graph. One is x-axis which is horizontal line on the graph and the other is y-axis which is vertical side of the graph. The point where x-axis and y-axis meet is origin which has value 0. The equation to write the points of the graph is represented by y(x) = 0. In the given equation there is t variable used in the values.

4 0
3 years ago
A flat screen television has a 50 inch diagonal and a height of 25 inches. How wide is the television rounded to the nearest ten
Lyrx [107]

Answer: 43.3 inches.

Step-by-step explanation:

According to the Pythagorean Theorem:

a^2=b^2+c^2

Where "a" is the hypotenuse, and "b" and "c" are the legs of the right triangle.

Let be "c" the width of the television.

We can indentify in the figure that:

a=50in\\b=25in

Then, we can substitute values and solve for "c":

(50in)^2=(25in)^2+c^2\\\\c=\sqrt{(50in)^2-(25in)^2}\\\\c=43.30in

Rounded to the nearest tenth:

c=43.3in

3 0
3 years ago
The length of a rectangular flower garden is 9 feet and it’s width is 5 feet how many feet of fencing will be needed
Tju [1.3M]
Use the simple perimeter formula.
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P = 2(9) + 2(5)
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Therefore 29ft of fencing will be needed.
8 0
3 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
HELP!!! WILL GIVE BRAINLIEST!!!! The agriculture department of a university works with individuals wanting to build greenhouses
Zanzabum

Answer:

D ... y= 3,450/ 1=10.13e^-0.2854

Step-by-step explanation:

3 0
3 years ago
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